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daser333 [38]
4 years ago
11

Finding which number supports the idea that the rational numbers are dense in the real numbers?

Mathematics
1 answer:
allsm [11]4 years ago
5 0

Answer: The terminating decimal between -3.14 and -3.15

Step-by-step explanation: The terminating decimal supports the idea because between -3.14 and -3.15, you are showing that rational numbers include integers,because integers also include negative numbers.

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Answer:

Circumference: 12π + 8 cm,

Area: 48 ( cm )^2

Step-by-step explanation:

This figure is composed of circles, squares, and semicircles. As you can see, the squares indicate that each semicircle should have ( 1 ) the same area, and ( 2 ) the same length ( circumference ). It would be easier to take the circumference of the figure first, as it is composed of arcs part of semicircles the same length.

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Circumference of Figure (composed of 6 semicircles + 2 sides of a square),

We know that 6 semicircles should be 6 * 2π, and as the sides of a square are equal - if one side is 4 cm, the other 3 are 4 cm as well. Therefore the " 2 sides of a square " should be 2

Circumference of Figure = 6 * 2π + 2 = 12π + 8 ( cm )

_____________

The area of this figure is our next target. As you can see, it is composed of 3 semicircles, and the area of 3 semicircles subtracted from the area of 3 squares. Therefore, let us calculate the area of 1 semicircle, and the area of 1 square first.

Area of 1 semicircle = 1/2πr^2 = 1/2π(2)^2 = 2π ( cm ),

Area of 1 square = ( 4 cm )( 4 cm ) = 16 ( cm^2 )

So, the area of the figure should be the following -

Area of Figure = 3 * 2π + 3( 16 - 2π ) = 48 ( cm )^2

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