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Dennis_Churaev [7]
3 years ago
11

Write an expression for the instantaneous voltage ????(????) delivered by an ac generator supplying 120 V rms at 60 Hz. Assume t

he voltage is 0 at time ????=0, and leave the factors in exact form; do not round their values. Write the argument of the sinusoidal function to have units of radians, but omit the units.
Physics
1 answer:
mart [117]3 years ago
6 0

Answer:

V = 120 \sqrt {2} sin (120 \pi t)

Explanation:

We start from the ideal conditions previously given, as well

V_ {rms} = 120V

f = 60Hz

We understand that the formula for Maximum Voltage is given by,

V_ {max} = \sqrt {2} V_ {rms}

In turn, we can take the expression given for the Instantaneous Voltage, which is defined as,

V = \sqrt {2} V_ {rms} sin (2 \pi f t)

Replacing all expressions in one,

V = 120 \sqrt {2} Vsin (2 \pi (60Hz) t)

V = 120 \sqrt {2} V sin ((120 \pi rad / s) t)

Eliminating units for better reading

V = 120 \sqrt {2} sin (120 \pi t)

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A book that weighs 20 N sits on a table. How big and in what direction does the force of gravity from the Earth act on the book?
taurus [48]

Answer:

A. 20 N down

Explanation:

It's asking how much force of gravity is acting on it. The book weighs 20 Newtons so that's how much gravity is being applied. Hope this helps

7 0
3 years ago
Read 2 more answers
21/33
postnew [5]

Answer:

400N

Explanation:

5 0
3 years ago
The equation of a wave is represented by: Y = 0.005sin 2π(0.5x – 200t) where x and y are in meters and t in seconds. Find its i.
lys-0071 [83]

Answer:

See solution below

Explanation:

The standard equation of a wave is represented by: Y = Asin 2π(x/λ – ft)

A is the amplitude

λ is the wavelength

f is the frequency

t is the time

Comparing the standard with the given equation Y = 0.005sin 2π(0.5x – 200t)

i) A = 0.005m

Amplitude is 0.005m

ii) ω = 2πf

ω = 2π(200)

ω = 400π rad/s

iii) ω = 2πf

400π = 2πf

200 = f

Swap

f = 200Hertz

iv) Period = 1/f

Period = 1/200

Period = 0.005secs

v) wave number  =

vi) Wavelength λ

0.5x = x/λ

0.5 = 1/λ

λ  = 1/0.5

λ = 2m

vii) velocity - fλ

velocity = 200 * 2

velocity = 400m/s

7 0
3 years ago
In a 120-volt circuit having a resistance of 12 ohms, the power W in watts when a current I is flowing through is given by W=120
Mrac [35]

Answer:

maximum power = 300 W

Explanation:

Ohm's law: Ohm's law state that the current flowing through a metallic conductor, is directly proportional to the potential difference applied across its end. mathematically it is expressed as,

V = IR............. Equation 1

Where V = potential difference, I = current, R = Resistance of the conductor.

If the power flowing through is gives as

W = 120I - 12I² ..................... Equation 2

To get the maximum power we differentiate of equation 2  and equate to zero

dW/dt = 0

120 - 24l = 0........................... equation 3

Making I the subject of the equation,

I = 120/24 = 5 A.

Suubstituting the value of I into Equation 2

W = 120 (5) - 12(5)²

W = 600 - 300

W = 300 W.

Therefore maximum power = 300 W

5 0
4 years ago
A system consists of a disk of mass 2.33 kg and radius 50 cm upon which is mounted an annular cylinder of mass 2.20 kg with inne
Gekata [30.6K]

Answer:

Kinetic energy of the system = 2547.41 Joules.

Explanation:

Given:

Disk:

Mass of the disk (m) = 2.33 kg

Radius of the disk (r) = 50 cm = \frac{50}{100} =0.5 m

Cylinder:

Mass of the annular cylinder (M) = 2.20 kg

Inner radius of the cylinder (R_i) = 0.2 m

Outer radius of the cylinder (R_o) = 0.3 m

The angular speed of the system (\omega) = 15.1 rev/s

Angular speed in in terms of Rad/sec = 15.1\times 2\pi =94.876 rad/sec

Formula to be used:

Rotational Kinetic energy, (KE)_r = \frac{I\times \omega^2}{2}

So, before that we have to work with the moment of inertia (MOI) of the system.

⇒ MOI of the system = MOI of the disk + MOI of the cylinder

⇒ MOI (system) = \frac{mr^2}{2} +\frac{M(R_i+R_o)^2}{2}

⇒ MOI (system) = \frac{2.33\times (0.5)^2}{2} + \frac{2.20\times (0.2+0.3)^2}{2}

⇒ MOI (system) = 0.566 kg.m^2

Now

The rotational Kinetic energy.

⇒ (KE)_r =\frac{I\omega^2}{2}

Plugging the values.

⇒  (KE)_r=\frac{0.566\times (94.876)^2}{2}

⇒ (KE)_r=2547.41 Joules

Then

The kinetic energy of the rotational system is 2547.41 J.

5 0
3 years ago
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