Answer:
A. 20 N down
Explanation:
It's asking how much force of gravity is acting on it. The book weighs 20 Newtons so that's how much gravity is being applied. Hope this helps
Answer:
See solution below
Explanation:
The standard equation of a wave is represented by: Y = Asin 2π(x/λ – ft)
A is the amplitude
λ is the wavelength
f is the frequency
t is the time
Comparing the standard with the given equation Y = 0.005sin 2π(0.5x – 200t)
i) A = 0.005m
Amplitude is 0.005m
ii) ω = 2πf
ω = 2π(200)
ω = 400π rad/s
iii) ω = 2πf
400π = 2πf
200 = f
Swap
f = 200Hertz
iv) Period = 1/f
Period = 1/200
Period = 0.005secs
v) wave number =
vi) Wavelength λ
0.5x = x/λ
0.5 = 1/λ
λ = 1/0.5
λ = 2m
vii) velocity - fλ
velocity = 200 * 2
velocity = 400m/s
Answer:
maximum power = 300 W
Explanation:
Ohm's law: Ohm's law state that the current flowing through a metallic conductor, is directly proportional to the potential difference applied across its end. mathematically it is expressed as,
V = IR............. Equation 1
Where V = potential difference, I = current, R = Resistance of the conductor.
If the power flowing through is gives as
W = 120I - 12I² ..................... Equation 2
To get the maximum power we differentiate of equation 2 and equate to zero
dW/dt = 0
120 - 24l = 0........................... equation 3
Making I the subject of the equation,
I = 120/24 = 5 A.
Suubstituting the value of I into Equation 2
W = 120 (5) - 12(5)²
W = 600 - 300
W = 300 W.
Therefore maximum power = 300 W
Answer:
Kinetic energy of the system = 2547.41 Joules.
Explanation:
Given:
Disk:
Mass of the disk (m) =
kg
Radius of the disk (r) =
cm =
m
Cylinder:
Mass of the annular cylinder (M) =
kg
Inner radius of the cylinder
=
m
Outer radius of the cylinder
=
m
The angular speed of the system
=
rev/s
Angular speed in in terms of Rad/sec =
rad/sec
Formula to be used:
Rotational Kinetic energy,
= 
So, before that we have to work with the moment of inertia (MOI) of the system.
⇒ MOI of the system = MOI of the disk + MOI of the cylinder
⇒ MOI (system) = 
⇒ MOI (system) = 
⇒ MOI (system) =
kg.m^2
Now
The rotational Kinetic energy.
⇒ 
Plugging the values.
⇒ 
⇒
Joules
Then
The kinetic energy of the rotational system is 2547.41 J.