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Ad libitum [116K]
4 years ago
14

Suppose that two objects attract each other with a gravitational force of 2 N. If the mass of one object is doubled, the other m

ass is tripled, and the distance between masses was cut in half what would be the new force of attraction between the two objects? *
1 point
a. 12 N
b. 48 N
c. 6 N
d. 24 N
Physics
2 answers:
inna [77]4 years ago
4 0
D I’m not as sure though
xxMikexx [17]4 years ago
3 0
D because it’s the right one
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A bullet of mass 0.016 kg traveling horizontally at a speed of 280 m/s embeds itself in a block of mass 3 kg that is sitting at
ivanzaharov [21]

(a) 1.49 m/s

The conservation of momentum states that the total initial momentum is equal to the total final momentum:

p_i = p_f\\m u_b + M u_B = (m+M)v

where

m = 0.016 kg is the mass of the bullet

u_b = 280 m/s is the initial velocity of the bullet

M = 3 kg is the mass of the block

u_B = 0 is the initial velocity of the block

v = ? is the final velocity of the block and the bullet

Solving the equation for v, we find

v=\frac{m u_b}{m+M}=\frac{(0.016 kg)(280 m/s)}{0.016 kg+3 kg}=1.49 m/s

(b) Before: 627.2 J, after: 3.3 J

The initial kinetic energy is (it is just the one of the bullet, since the block is at rest):

K_i = \frac{1}{2}mu_b^2 = \frac{1}{2}(0.016 kg)(280 m/s)^2=627.2 J

The final kinetic energy is the kinetic energy of the bullet+block system after the collision:

K_f = \frac{1}{2}(m+M)v^2=\frac{1}{2}(0.016 kg+3 kg)(1.49 m/s)^2=3.3 J

(c) The Energy Principle isn't valid for an inelastic collision.

In fact, during an inelastic collision, the total momentum of the system is conserved, while the total kinetic energy is not: this means that part of the kinetic energy of the system is losted in the collision. The principle of conservation of energy, however, is still valid: in fact, the energy has not been simply lost, but it has been converted into other forms of energy (thermal energy).

4 0
4 years ago
You are riding your bike to the mall. You travel the first mile in 10 minutes. The last mile takes you 15 minutes. This is an ex
Vikki [24]
This is an example of slowing down because you encountered heavy traffic or just got tired. Also, the numbers show acceleration.
6 0
4 years ago
Soil can best be described as the
mr Goodwill [35]
C. It is C because it really is loose covering.
7 0
3 years ago
What is the magnitude and direction of the electric field atradiaConsider a coaxial conducting cable consisting of a conductingr
Alexxx [7]

Answer:

 E = 9.4 10⁶ N / C ,     The field goes from the inner cylinder to the outside

Explanation:

The best way to work this problem is with Gauss's law

             Ф = E. dA = qint / ε₀

 

We must define a Gaussian surface, which takes advantage of the symmetry of the problem. We select a cylinder with the faces perpendicular to the coaxial.

The flow on the faces is zero, since the field goes in the radial direction of the cylinders.

The area of ​​the cylinder is the length of the circle along the length of the cable

         dA = 2π dr L

          A = 2π r L

They indicate that the distance at which we must calculate the field is

         r = 5 R₁

         r = 5 1.3

         r = 6.5 mm

The radius of the outer shell is

         r₂ = 10 R₁

         r₂ = 10 1.3

         r₂ = 13 mm

         r₂ > r

When comparing these two values ​​we see that the field must be calculated between the two housings.

Gauss's law states that the charge is on the outside of the Gaussian surface does not contribute to the field, the charged on the inside of the surface is

         λ = q / L

         Qint = λ L

Let's replace

      E 2π r L = λ L /ε₀

       E = 1 / 2piε₀  λ / r

Let's calculate

         E = 1 / 2pi 8.85 10⁻¹²  3.4 10-12 / 6.5 10-3

         E = 9.4 10⁶ N / C

The field goes from the inner cylinder to the outside

5 0
3 years ago
What is the mass of a bullet moving at 970m/s if the bullet’s KE is 3.9x 10^3J
motikmotik

Answer:

0.08kg

Explanation:

K.E = 1/2 mv^2

v = 970m/s

K.E = 3.9x 10^3J= 3900J

K.E = 1/2 mv^2

3900 = 1/2 m x 970x 970

3900 = 1/2 ×940900m

3900 = 470450m

m = 3900/470450 = 0.00828993516 = 0.008kg

4 0
4 years ago
Read 2 more answers
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