<h3>Answer: </h3>
1g= 1000 mg
1mg = 1÷ 1000 g
therefore, 0.017mg= 0.000017 or
grams
We can use the idea gas law equation to find the number of moles of He in the balloon at STP
PV = nRT
where
P - standard pressure - 10⁵ Pa
V - volume - 3.8 x 10⁻³ m³
n - number of moles
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - standard temperature - 273 K
substituting these values in the equation
10⁵ Pa x 3.8 x 10⁻³ m³ = n x 8.314 Jmol⁻¹K⁻¹ x 273 K
n = 0.17 mol
number of He moles are 0.17 mol
Answer:
B. Are fixed within electron orbitals
Explanation:
Electrons are found in the energy levels
<u>Given:</u>
# Molecules of NaOH = 1.50 * 10²³
<u>To determine:</u>
The # moles of NaOH present in the given molecules
<u>Explanation:</u>
By definition:
1 mole of NaOH corresponds to Avogadro's number i.e. 6.023*10²³ molecules
Therefore the moles of NaOH corresponding to the given molecules would be = 1.50*10²³ molecules NaOH * 1 mole NaOH/6.023*10²³ molecules NaOH
= 0.249 moles
Ans: 0.249 moles of NaOH
Answer:
When aqueous solutions of silver(I) acetate and manganese(II) iodide are combined, an insoluble precipitate of silver(I) iodide is formed
Explanation:
- It is an example of precipitation reaction.
- When aqueous solutions of silver(I) acetate and manganese(II) iodide are combined, an insoluble precipitate of silver(I) iodide is formed.
- Precipitation of silver(I) iodide is confirmed by it's yellow color.
- Hence a reaction is observed.
- Molecular reaction: