What triangle I don’t see one I just see a 32?
Answer:
19
Step-by-step explanation:
4 × ( 3/ 4 − 1/ 2 ) + 3 × 6
PEMDAS
Parentheses first
4 × ( 3/ 4 − 2/4 ) + 3 × 6
4 × ( 1/4 ) + 3 × 6
Then multiply and divide from left to right
1 + 18
19
i. Line BD = 6√2 cm
ii. Perimeter = 3 (π + 4) cm
iii. Area = 18 ( π - 2) cm
<h3>How to determine the parameters</h3>
Let the length of BD = x
Since B is the midpoint of the arc AC, then ∠BOC = 15°
In ΔBDB
Let's use the trigonometric ration, tan
CD = x
Then, using the Pythagorean theorem
Thus, line BD is cm
ii. Perimeter = BC + BD + CD
= 2πr/8 + x + r - x
= π(12)/4 + r
= 3π + 12
= 3 ( π + 4) cm
iii. Area of shaded area = Area of BOC + Area of BOD
⇒ πr^2/8 × 1/2x^2
= π144/8 × 1/2(72)
= 18π - 36
= 18 ( π - 2) cm²
Learn more about quadrant of a circle here:
https://brainly.in/question/1591300
#SPJ1
Answer:
please give the complete question.
(y-6)^ ??
Algebra is really easy when you try your hardest. What seems to be troubling you friend?