No because they can be seperated differently
For
the reaction 2SO2 + O2 -> 2 SO3, we first determine which is the excess
reactant between SO2 and O2. We list down the molar mass of the reactants:
Molar
mass of SO2 = 64.0638 g/mol
Molar
mass of O2 = 32 g/mol
Using
the stoichiometry of the reaction, we then calculate the amount of oxygen that
will react with 90.0 g of SO2.
90.0
g SO2 x 1 mol SO2/64.0638 g x 1 mol O2/ 2 mol SO2 x 32 g O2/mol = 22.4776 g O2
<span>
</span>
<span>Thus,
we can conclude that O2 is the excess reactant while SO2 is the limiting
reactant. Subtracting 22.4776 g O2 from the initial 100.0 g O2, we get 77.5224
g O2 left after the complete reaction of 90.0 g SO2. </span>
Answer:
0.4941, 0.5059
Explanation:
= Partial pressure of nitrogen = 417 mm Hg
= Partial pressure of xenon = 427 mm Hg
Total pressure in the system is given by
Mole fraction is given by
For xenon
or
So, mole fraction of nitrogen is 0.4941 and xenon is 0.5059.