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4 years ago

19.

Physics

2 answers:

OLEGan [10]4 years ago

8 0

I believe that it is C.

mihalych1998 [28]4 years ago

7 0

Fg is the symbol for gravitational force.

Answer: C. Fg.

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A person scuffing her feet on a wool rug on a dry day accumulates a net charge of -52 µc. how many excess electrons does this pe

LenKa [72]

Using q=1.60217662 E-19 C we get:
$\frac{52 \times 10^-^6}{1.60217662 \times 10^-^1^9}=3.24558 \times 10^1^4 electrons$
Then using 9.10938356E-31 kg as the mass, we get
$(3.24558 \times 10^1^4)(9.10938356\times 10^-^3^1)=2.95653\times 10^-^1^6kg$

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3 years ago

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How does refraction support the particle theory of light? Particles bounce off surfaces similar to the way in which a ball bounc

AnnyKZ [126]

Forces act on the particles to push or pull them from one medium to another.

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3 years ago

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A 0.600 m long pendulum is used to determine the acceleration due to gravity on a distant planet. If 20 complete oscillation are

givi [52]

Answer :

Explanation :

It is given that,

length of pendulum, l = 0.6 m

Number of oscillation, n = 20

time, t = 35.5 seconds

so, Time period, $T=\dfrac{t}{n}$

$T=\dfrac{35.5s}{20}$

we know that the time period of pendulum is given by

$T=2\pi\sqrt{\dfrac{l}{g}}$

$g=\dfrac{4\pi^2l}{T^2}$

$g=\dfrac{4\times(3.14)^2\times 0.6 \times (20)^2}{(35.5s)^2}$

$g=7.51\ m/s^2$

$g=7.52\ m/s^2$

6 0

3 years ago

A plane is flying east at 115 m/s. The wind accelerates it at 2.88 m/s^2 directly northwest. After 25.0s, what is the magnitude

kondaur [170]

Answer:

81.8 m/s

Explanation:

The initial velocity of the plane is:

$v_0=115 m/s$ (toward east)

So, decomposing along the x- and y- directions:

$v_{x0} = 115 m/s\\v_{y0} = 0$

(we took east as positive x-direction and north as positive y-direction)

The acceleration is

$a=2.88 m/s^2$ (northwest, so the angle with the positive x-direction is 135 degrees)

Decomposing it along the two directions:

$a_x = a cos 135^{\circ} = (2.88 m/s^2)(cos 135^{\circ})=-2.04 m/s^2\\a_y = a sin 135^{\circ} = (2.88 m/s^2)(sin 135^{\circ})=2.04 m/s^2$

So the two components of the velocity after a time t = 25.0 s will be

$v_x = v_{x0} + a_x t = 115 m/s + (-2.04 m/s^2)(25.0 s)=64 m/s\\v_y = v_{y0} + a_y t = 0 m/s + (2.04 m/s^2)(25.0 s)=51 m/s$

So, the magnitude of the velocity of the plane will be

$v=\sqrt[v_x^2+v_y^2}=\sqrt{(64 m/s)^2+(51 m/s)^2}=81.8 m/s$

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3 years ago

The major problem with hydrogen as an alternative source of energy is that none exists on the surface of the earth. True or fals

Brut [27]

That statement is as false as false can be.

Roughly 78% of the Earth's surface is covered by water,
and Hydrogen is a major component of water.

On the surface of the Earth, you really have to try hard
to be far away from a cheap source of Hydrogen.

8 0

3 years ago