Answer:
The correct answer is 7.1 degree C.
Explanation:
Based on the given information, the initial temperature or To of the block is 23.4 degree C.
The energy lost or Q from the given wooden block is -759 J.
The specific heat capacity or c of the wood given is 1.716 J/g°C
The mass of the wooden block given is 27.2 grams.
There is a need to find the final temperature of the wooden block, for this the formula to be used is,
Q = m × c × (T-To)
Now by putting the given values in the formula we get,
-759 = 27.2 × 1.716 (T - 23.4)
T = 7.1 degree C.
Answer:
The internal energy of a system <u>is the sum of the potential and kinetic energies of the components</u>
Explanation:
Internal energy is defined as the sum of two types of energy: kinetic energy and potential energy.
Kinetic energy is defined as the sum of all the kinetic energies that each element has within a system with respect to its center of mass. It is caused by the movement of particles. Meanwhile, the potential energy is the energy that is associated with each of the interactions. Potential energy is associated with the constituents of matter, of the electrostatic energy of each atom that is inside the molecules.
You need to add the last substance to the products side(the right sode of the arrow). You have hydrogen and oxygen - water.
You get: BrO3 + N2H4 -> Br2 + N2 + H2O
# of Br: 1x1 = 1 # of Br: 2x1 = 2
O: 3x1 = 3 O: 1x1 = 1
N: 2x1 = 2 B N: 2x1 = 2
H: 4x1 = 4. H: 2x1 = 2
Br:
Multiply the reactant (left) side by 2 to balance.
O:
You've just multiplied the reactant oxygen by 2 so now the reactant side equals 6. Multiply the product (right) side by six as well.
H:
The product side is now equal to 12. Multiply the reactant side by 3 to balance.
N:
Now you have to balance N because the reactant side has been risen. So multiply the product side by three as well.
You end up with the complete and balanced equation:
2BrO3 + 3N2H4 -> Br2 + 3N2 + 6H2O
<span>0.333 ounce * 0.75 * 28.35 grams/ounce = 7.080 grams gold
7.080 grams Au / 196.967g/mol Au = 0.0359 mol Au
0.0359 mol Au * (6.023 * 10^23) atoms/mol = 2.24 * 10^22 Atoms Au</span>