The angular frequency of this motion is 5.46 rad/s.
The oscillation of spring is an example of Simple Harmonic Motion(SHM).
The general equation of an SHM is given by the formula.
X = Acos(wt)
Here A is the amplitude
ω is the angular frequency
T is the time
Comparing the above equation with the given condition,
X = 17.4 cm cos(5.46t)
A = 17.4 cm
ω = 5.46 rad/s
T = 1 s
Hence, the angular frequency of this motion is 5.46 rad/s.
To know more about the "general equation of SHM", refer to the link below:
brainly.com/question/14869852?referrer=searchResults
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Answer:
0.572
Explanation:
First examine the force of friction at the slipping point where Ff = µsFN = µsmg.
the mass of the car is unknown,
The only force on the car that is not completely in the vertical direction is friction, so let us consider the sums of forces in the tangential and centerward directions.
First the tangential direction
∑Ft =Fft =mat
And then in the centerward direction ∑Fc =Ffc =mac =mv²t/r
Going back to our constant acceleration equations we see that v²t = v²ti +2at∆x = 2at πr/2
So going backwards and plugging in Ffc =m2atπr/ 2r =πmat
Ff = √(F2ft +F2fc)= matp √(1+π²)
µs = Ff /mg = at /g √(1+π²)=
1.70m/s/2 9.80 m/s² x√(1+π²)= 0.572
When I went through with the math, the answer I came upon was:
<span>6.67 X 10^14 </span>
<span>Here is how I did it: First of all we need to know the equation. </span>
<span>c=nu X lamda </span>
<span>(speed of light) = (frequency)(wavelength) </span>
<span>(3.0 X 10^8 m/s) = (frequency)(450nm) </span>
<span>We want the answer in meters so we need to convert 450nm to meters. </span>
<span>450nm= 4.5 X 10^ -7 m </span>
<span>(3.0 X 10^8 m/s) = (frequency)(4.5 X 10^ -7 m) </span>
<span>Divide the speed of light by the wavelength. </span>
<span>(3.0 X 10^8m/s) / (4.5 X 10^ -7m) =6.67 X 10^ 14 per second or s- </span>
<span>Answer: 6.67 X 10^14 s- hope this helps</span>
Answer:
B
Explanation:
Use conservation of momentum: Total momentum of the system before is the same as the total momentum after the collision. Since both are moving north, the momentum of both cars is in the same direction, and the total momentum before collision is 1000kg*20m/s + 1500kg*36m/s = 74000kg-m/s.
This is the same amount of momentum after collision, and since they are locked together, their mass is added. The velocity can be found by: 74000kg-m/s ÷ 2500kg = 29.6m/s.
momentum = mass*velocity
C) An unbalanced force is acting on the car in the direction east