Solution: g + 1 ≠ 0,
Geometric figure: Hyperbola (on graph)
Answer:
12.29minutes
Step-by-step explanation:
The net flow rate = flow in - flow out = F(t) - E(t) = t+6/1+t - ln(t+2)/t+1 = [(t + 6) - ln(t+2)]/(t+1)
So, the amount of water present in the tank at time, t is A = net flow rate × time = [(t + 6) - ln(t+2)]/(t+1) × t = t[(t + 6) - ln(t+2)]/(t+1)
At t = 10 minutes,
A = t[(t + 6) - ln(t+2)]/(t+1)
A = 10[(10 + 6) - ln(10+2)]/(10+1)
A = 10[16 - ln12]/11
A = 10[16 - 2.485]/11
A = 10[13.515]/11
A = 135.15/11
A = 12.29 minutes
Sender would be 4 x 7 divided by 15
Answer:
Step-by-step explanation:
assuming that the X is a multiplication symbol and not a variable, because the multiplication symbol is * not x, 5*5/2*7=25/14=1 and 11/14