Answer:
6.6 x 10⁻⁵ mol/L
Explanation:
First, we have to convert the moles from μmol to mol:
moles of solute= 33.0 μmol x (1 x 10⁶ mol)/1 μmol = 3.3 x 10⁻⁵ mol
Then, we convert the volume from mL to L:
volume = 500.0 mL x 1 L/1000 mL = 0.5 L
Finally, we calculate the concentration of the solution in mol/L by dividing the moles into the volume in liters, as follows:
mol/L = moles of solute/volume = 3.3 x 10⁻⁵ mol/(0.5 L) = 6.6 x 10⁻⁵ mol/L
Answer:
6.02×10^23 atoms
Explanation:
Avogadros constant is a number that states the amount of atoms in one mole of a substance which is 6.02×10^23 to 3 significant figures.
Since the addition of the H2O in the last step of hydroboration is anti-Markovnikov, the starting material is 1-pentyne.
The addition of H2 to C5H8 yields an alkene when a Lindlar catalyst is used. Recall that the Lindlar catalysts poisons the process so that the addition do not go on to produce an alkane.
When hydroboration is carried out on the alkene, we are told that a primary alcohol was obtained. We must note that in the last step of hydroboration, water is added in an anti- Markovnikov manner to yield the primary alcohol. Hence, the starting material must be 1-pentyne as shown in the image attached.
Learn more: brainly.com/question/2510654
FeO + Al -> AlO + Fe
As you can see, this type of reaction would lead to be a Single Placement (or Replacement) reaction!
Hope this helps! Best wishes!