All categories

3 years ago

Write the following number in standard form.

Mathematics

1 answer:

I am Lyosha [343]3 years ago

8 0

Answer:

The third one, 104,000,027,571

Step-by-step explanation:

The first and second ones are not the answers because the problem does not say one hundred forty billion.

The last one is not the answer because the problem doesn't say two hundred seventy thousand.

Thus leaving the third one, which fits the description of the number.

You might be interested in

Sasha has 3.20 in U.S. coins. She has the same number of quarters and nickels. What is the greatest number of quarters she could

RSB [31]

Answer:

10 quarters = $2.50

10 nickels = $0.50

that leaves $0.20 for other coins (dimes / pennies)

Step-by-step explanation:

First, suppose she has only quarters and nickels and no other coins. Then if C is the identical number of coins of each type, then 5C + 25C = 320, so 30C = 320 and 3C = 32, but there is no integer solution to this. So she must have at least one other type of coin.

Assume she has only quarters, nickels, and dimes. Then if D is the number of dimes, 5C + 25C + 10D = 320, which means 30C + 10D = 320, or 3C + D = 32. The smallest D can be is 2, leaving 3C = 30 and thus C = 10. So in this scenario she would have 10 quarters, 10 nickels, and two dimes to make $2.50 + $0.50 + $0.20 = $3.20.

This has to be the highest number, because if she had 11 quarters and 11 nickels, that alone would add up to 11(0.25) + 11(0.05) = $3.30, which would already be too much.

8 0

3 years ago

Read 2 more answers

Work out the percentage change when a price of £20 is decreased to £3.

mestny [16]

Answer:

i can not see anything is it me or is it you please tell me so i can awnser it

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

If lines AB and CD are parallel, then angles C and E are

lys-0071 [83]

Answer: Angles C and E are same side interior angles.

Step-by-step explanation:

8 0

3 years ago

Choose all that give the correct expression for the quantity described. The difference of nine times a number x and the quotient

ohaa [14]

Step-by-step explanation:

We are to get the expression for the following statements;

1) The difference of nine times a number x and the quotient of that number and 5.

The product of nine and a number x is expressed as;

$=9 \times x\\= 9x$

The quotient of that number and 5.

$= \frac{x}{5}$

The difference between both expression;

$9x - \frac{x}{5}$

Hence, the difference of nine times a number x and the quotient of that number and 5 is expressed as $9x - \frac{x}{5}$

2) Eight more than the quotient of twelve and a number n

Quotient of twelve and a number n is expressed as:

$\frac{n}{12}$

Eight more than the resulting function is;

$\frac{n}{12}+8$

Hence eight more than the quotient of twelve and a number n is expressed as $\frac{n}{12}+8$

3) The product of a number and the quantity 'six minus the number' plus the quotient of eight and the number.

Let the number be x:

six minus the number is expressed as;

$6-x$

product of a number x and the quantity 'six minus the number is;

$x(6-x)$

quotient of eight and the number is;

$\frac{8}{x}$

Taking the resulting sum of the last two expression

$x(6-x) + 8x$

Hence the product of a number and the quantity 'six minus the number' plus the quotient of eight and the number is expressed as;

$x(6-x) + 8x$

4) Sum of three consecutive even integers. 2x + (2x + 2) + (2x + 4).

Let the first even number be 2x

The consecutive even numbers are gotten by adding 2 to the preceding number. The two consecutive even integers are 2x+2 and 2x+2+2

the sum of three consecutive even integers is expressed as;

$= 2x +(2x+2)+(2x+2+2)\\= 2x+(2x+2)+(2x+4)$

4 0

3 years ago

A new test to detect TB has been designed. It is estimated that 88% of people taking this test have the disease. The test detect

Elodia [21]

Answer:

Correct option: (a) 0.1452

Step-by-step explanation:

The new test designed for detecting TB is being analysed.

Denote the events as follows:

<em>D</em> = a person has the disease

<em>X</em> = the test is positive.

The information provided is:

$P(D)=0.88\\P(X|D)=0.97\\P(X^{c}|D^{c})=0.99$

Compute the probability that a person does not have the disease as follows:

$P(D^{c})=1-P(D)=1-0.88=0.12$

The probability of a person not having the disease is 0.12.

Compute the probability that a randomly selected person is tested negative but does have the disease as follows:

$P(X^{c}\cap D)=P(X^{c}|D)P(D)\\=[1-P(X|D)]\times P(D)\\=[1-0.97]\times 0.88\\=0.03\times 0.88\\=0.0264$

Compute the probability that a randomly selected person is tested negative but does not have the disease as follows:

$P(X^{c}\cap D^{c})=P(X^{c}|D^{c})P(D^{c})\\=[1-P(X|D)]\times{1- P(D)]\\=0.99\times 0.12\\=0.1188$

Compute the probability that a randomly selected person is tested negative as follows:

$P(X^{c})=P(X^{c}\cap D)+P(X^{c}\cap D^{c})$

$=0.0264+0.1188\\=0.1452$

Thus, the probability of the test indicating that the person does not have the disease is 0.1452.

4 0

3 years ago