Answer:
7
Step-by-step explanation:
$45- $8 = 37 (aka his raffle ticket spending money)
37÷5= 7, so the max # of raffle tickets he can buy is 7.
A. Profit (P):
P = 100 x
Revenue (R) is Profit – Cost:
R = P – C
R = 100 x – [2750 + 8x + 0.1x^2]
R = 100x – 2750 – 8x – 0.1x^2
R = -0.1x^2 + 92x – 2750
B.
To make a profit, R must be zero, R = 0:
0 = -0.1x^2 + 92x – 2750
x^2 – 920x = - 27,500
Completing the square:
<span>x^2 – 920x + 211,600 = - 27,500 + 211,600</span>
(x – 460)^2 = 184,100
x – 460 = ± 429.07
x = 30.93, - 889.07
Therefore sell at least 31.
31<x<500
<span> </span>
Answer:
x = 28
Step-by-step explanation:
ΔARP ≈ ΔCRD
42/x = 57/(10+x)
cross-multiply:
42(10+x) = 57x
420 + 42x = 57x
420 = 15x
28 = x
8X + 8 > 7x + 14
subtract 7x and 8 from both sides
x > 6
19 square units?
I hope this works if not lemme know