Initial velocity v = 86.6 m / s
angle ,theta = 63.7 degrees
(A). the horizontal component of the shell's initial velocity = v cos 63.7 = 38.36 m / s
vertical component of shells' initial velocity = v sin 63.7 = 77.63 m / s
(B). time taken to reach maximu height t = v sin (theta ) / g
= 7.922 s
(C). Maximum height H = ( v sin(theta) )^ 2/ 2g
= 307.5 m
(D). Required distance = v^ 2 *sin2(theta) / g
= 607.9 m
(E). Horizontal component of accleraton = 0
vertical component of accleration = g = 9.8 m / s^ 2
(F). horizontal component of velocity at required point = v cos (theta ) = 38.36 m / s
vertical compoent of velocity at required point = 0
The density of silver is
Explanation:
The density of an object is given by the following equation:
where
d is the density
m is the mass of the sample
V is its volume
For the sample of silver in this problem, we have:
m = 2500 g (mass)
(volume)
Therefore, the density of silver is:
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Answer:
a) Effective resistance when diode was forward biased = 0 Ω
b) Effective resistance when diode was reverse biased = ∞ Ω
Explanation:
Please refer attached characteristic curve for diode.
a) As per the characteristic curve, when the diode was forward biased by 0.7 Volt theoretically infinite current was flowing across the diode.
Hence effective resistance for the diode in forward biased = = 0 Ω
b) As per the characteristic curve, when the diode was reversed biased by 0.7 Volt theoretically zero (0 amp) current was flowing across the diode.
Hence effective resistance for the diode in forward biased = = ∞ Ω
Answer:0.8 meter
Explanation:
Frequency=426.7hz
Velocity=346m/s
Length =velocity ➗ frequency
Length=346 ➗ 426.7
Length =0.8
Explanation:
It is known that the relation between force and acceleration is as follows.
F = -ma ............ (1)
Also, acceleration (a) = ......... (2)
The given data is as follows.
v = 0, u = 14 m/s, s = 1
Therefore, putting the values of expression (2) into expression (1) as follows.
F =
=
= 5978 N
thus, we can conclude that net force on the person if he or she is wearing a seat belt and if the air bag deploys is 5978 N.