Answer:
y2= 2x-4
y3=6x-1
y4= x-1
y5=2x
Step-by-step explanation:
for y=2x-1
1) for a vertical translation down of 3 units
y2= y-3 =(2x-1)-3= 2x-4
y2= 2x-4
2) for a slope increased by 4
y3= y+ 4x = 2x-1 +4x = 6x-1
y3=6x-1
3) for sloped divided in half. slope of y : m=2 → slope of y4=2/2 =1
y4= x-1
4) shifted up (vertical translation) of 1 unit
y5= y+1 = 2x-1+1=2x
y5=2x
Answer:
-5, -13, -21
Step-by-step explanation:
your subtracting 3 each time
Answer: 21 units²
Step-by-step explanation:
Since there is a pair of parallel sides, this figures is a trapezoid. The formula for the area of a trapezoid is
, where a and b are the parallel sides and h is the height.
Here, a and b are 5 and 9, while 3 is the height. Let's put all 3 values into the formula.
![A=\frac{1}{2}(5+9)*3](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7D%285%2B9%29%2A3)
<em> [Adding in the parentheses]</em>
<em>[Multiplying one-half by 14]</em>
<em />
<em>[Multiplying 7 and 3]</em>
<em />
The area is 21 units².
Let W and L be width and length of the rectangular pen respectively.
Therefore,
Circumference, C = 2W+2L= 130 yd
Area, A = LW = 1050 yd^2=> L = 1050/W
Using the circumference expression and substituting for L;
130 = 2W + 2(1050/W) = 2W+2100/W
130*W = 2W*W + 2100
130W = 2W^2 +2100
2W^2-130W+2100 = 0
Solving for W;
W= [-(-130)+/- Sqrt ((-130)^2-4(2)(2100)]/2*2 = 32.5+/- 2.5
W = 30 or 35 yd
When W = 30, L = 1050/30 = 35
When W = 35, L = 1050/35 = 30
Therefore, W = 30 yd and L = 35 yd.
Answer:
The waffle cone is $3.62.
First, say what your variables are.
w = large waffle cone
s = sugar cone
Next, create two equations given the data in the word problem.
![2.06 + s = w](https://tex.z-dn.net/?f=2.06%20%2B%20s%20%3D%20w)
![s = 1.56](https://tex.z-dn.net/?f=s%20%3D%201.56)
Because you have what the sugar cone is valued at, replace the s in the first equation with 1.56 and solve.
![2.06 + (1.56) = w](https://tex.z-dn.net/?f=2.06%20%2B%20%281.56%29%20%3D%20w)
![w = 3.62](https://tex.z-dn.net/?f=w%20%3D%203.62)