The limit is x---->4-
The negative show that x approaches from the left
Now
As x approaches 4 from the left ... Means This number should be less than 4 (<4) but really close to 4.
Let's pick a Number
Say 3.99
Substitute this... You have
3.99/3.99-4
3.99/-0.01
If we choose x to be 3.999
we will have
3.999/-0.001
Notice the pattern... As x approaches 4 from the left... This limit will approach NEGATIVE INFINITY
Why?
As you approach 4 from the left... 3.9,3.99,3.999... You notice that the denominator becomes negative and EXTREMELY SMALL... and when you divide by an extremely small Number..... You'll get a relatively HUGE VALUE(You can try this... Use a calc... Divide any number of choice by a very small number... say.. 0.0000001.... You'll get a huge result
In our case... The denominator is negative... So it Will Approach a very Huge Negative Number
Hence
Answer.. X WILL APPROACH NEGATIVE INFINITY.
Vertical asymptotes are the zeroes of the denominator of a function
The denom. is x-4
Equate to zero to get the asymptote
x-4=0
x=4
Hence... There will be a vertical asymptote at x=4.
Have a great day!
Answer:
I'm pretty sure it is 7.4% or 0.074.
Step-by-step explanation:
Answer:
No, it is not a solution
Step-by-step explanation:
Given
Required
Is (4,3) a solution?
(4,3) implies that:
So:
<em>Because 1 and 4 are not equal, then (4,3) is not a solution</em>
Answer:
There are 1% probability that the last person gets to sit in their assigned seat
Step-by-step explanation:
The probability that the last person gets to sit in their assigned seat, is the same that the probability that not one sit in this seat.
If we use the Combinatorics theory, we know that are 100! possibilities to order the first 99 passenger in the 100 seats.
LIke we one the probability that not one sit in one of the seats, we need the fraction from the total number of possible combinations, of combination that exclude the assigned seat of the last passenger. In other words the amount of combination of 99 passengers in 99 seats: 99!
Now this number of combination of the 99 passenger in the 99 sets, divide for the total number of combination in the 100 setas, is the probability that not one sit in the assigned seat of the last passenger.
P = 99!/100! = 99!/ (100 * 99!) = 1/100
There are 1% probability that the last person gets to sit in their assigned seat
Answer:
B
Step-by-step explanation:
If you’re looking for the intersection it’s B.