Formula:
F = ma
m = F÷A
m: mass F:force A: accelerarion
m = 450N ÷ 15m/s^2
= 30kg
Hope this helps :)
There is no illustration of the problem provided but I'll attempt to provide an answer.
The relationship between the electric potential difference between two points and the average strength of the electric field between those two points is given by:
║E║ = ΔV/d
║E║ is the magnitude of the average electric field, ΔV is the potential difference between A and B, and d is the distance between A and B.
We are given the following values:
║E║= 10N/C
d = 3m
Plug these values in and solve for ΔV
10 = ΔV/3
ΔV = 30V
<span>Miller Urey experiment's purpose was to test the chemical origin of life under the conditions supposed to be present on the early Earth.
</span>The scientists Miller and Urey heated a mixture of water<span>, </span>ammonia<span>, </span>methane<span> and </span>hydrogen<span> in a sterile flask until it evaporated water to produce water vapour. </span><span>Electric sparks were passed through the mixture of </span>water vapour and gases, simulating lightning. The experiment was done during one week. After a week, the contents were analysed and Miller and Uray proved that <span>several organic compounds could be formed spontaneously by simulating the conditions of Earth's early atmosphere.</span>
Answer: The net force is negative, The net force is positive, There is change in motion.
When an balanced force acts, there is change in motion. In case of balanced forces, the object does not change its motion. The unbalanced force causes change in the momentum of the object. There would be some net force. It would not be zero. The net force is zero when the acting forces are balanced. The net force in case of unbalanced forces have certain magnitude and are positive or negative depending on the direction. The positive and negative sign denotes direction of the net force.
Answer:
A 3.0 kg mass moving at 9.0 m/s has more momentum than taht of a 5.0 kg mass moving at 5.0 m/s
Explanation:
given two masses m1 and m2 and their corresponding velocities v1 and v2
m1 = 3 kg
m2 = 5 kg
v1 = 9 m/s
v2 = 5 m/s
To calculate momentum of the masses:
We know that the momentum is given by the equation:
p = mv, where m is mass and v is velocity
momentum of mass m1 , p1 = m1 x v1
= 3 x 9 = 27 kg.m/s
momentum of mass m2, p2 = m2 x v2
= 5 x 5 = 25 kg.m/s
Hence p1>p2
Comparing above momentum value, it is inferred that the momentum of mass 3.0 kg is more that the momentum of mass 5.0 kg.