Answer:
0.4386
Explanation:
<em>The density of an object is calculated as the ratio of its mass and that of its volume. This can be expressed mathematically as;</em>
Density = mass/volume
In this case:
density of lead = 1140 kg/m3
mass of the lead = 500 kg
From the equation above;
volume of the lead = mass/density
= 500/1140
= 0.4386
<em>Hence, the volume of 500 kg of lead with a density of 1140 kg/m^3 is </em><em>0.4386 </em><em>.</em>
Explanation:
We can solve the problem, either using graph or equation, as per our liking :
u = 12 m/s
v = - 8 m/s
t = 5 sec
(1) v = u + at
-8 = 12 + 5a
<u>a = - 4 m/s^2 </u>
<u>(</u><u>2</u><u>)</u> S = ut + 1/2 * a * t^2
S = 12 * 5 - 2 * 25
<u>S (Distance travelled) = 10 m</u>
Cotton is significantly less dense than iron. Therefore if you have equal volume samples of cotton and iron, the iron sample will weigh more than the cotton sample.
A substance's relative density is the ratio of its density to that of liquid water. You are taking two quantities with the same unit and dividing them. This will cancel out the unit on the top and bottom, leaving you with a number that has no unit.
Inflating a balloon puts it under an awful lot of pressure. The material must remain pretty durable throughout in order to sustain that much stress. Any weak spots inside the balloon will eventually give way; the balloon will then rip and pop.
<span>1.7 rad/s
The key thing here is conservation of angular momentum. The system as a whole will retain the same angular momentum. The initial velocity is 1.7 rad/s. As the person walks closer to the center of the spinning disk, the speed will increase. But I'm not going to bother calculating by how much. Just remember the speed will increase. And then as the person walks back out to the rim to the same distance that the person originally started, the speed will decrease. But during the entire walk, the total angular momentum remained constant. And since the initial mass distribution matches the final mass distribution, the final angular speed will match the initial angular speed.</span>