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3 years ago

689 divided by 5 Show your workings

Mathematics

1 answer:

Elis [28]3 years ago

8 0

Answer:

137.8 or 137 4/5

Step-by-step explanation:

You should do this as a long division problem:

1. first divide 68 by 5 which will be 13

2. 5x13 is 35 so you will subtract 65 from 68 on your long division problem the you carry everything down and solve it.

3. Next you will add you seven when you carry it down.

4. you will get 137 r 4.

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23. If XY = 13, XA = 4, and XZ = 26, then XB =

UkoKoshka [18]

Answer:

It is given that in triangle XYZ, XY = 13, YZ=20, and XZ=25.Using the law of cosines, we have

CosC=\frac{a^2+b^2-c^2}{2ab}

cosZ=\frac{(YZ)^2+(XZ)^2-(XY)^2}{2(YZ)(XZ)}

CosZ=\frac{(20)^2+(25)^2-(13)^2}{2(20)(25)}

CosZ=\frac{400+625-169}{1000}

CosZ=\frac{856}{1000}

CosZ=0.856

Z=cos^{-1}(0.856)

Z=37.13^{\circ}

Step-by-step explanation:

5 0

4 years ago

What is the area of a quadrilateral with vertices (1,2), (1,4), (2,2) and (2,4)? (Can you please show the work)?

nasty-shy [4]

check the picture below. You can pretty much just count the units from the grid.

8 0

4 years ago

How do you add integers with the same sign? PLEASE I NEED IT NOW AND THANK YOU

dedylja [7]

When you add integers, you keep the sign on the sum.

For example:
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3 0

3 years ago

If f(x) = 4 – x2 and g(x) = 6x, which expression is equivalent to (g – f)(3)?

Oduvanchick [21]

Remember that $(g-f)(x)$ is $g(x)-f(x)$ . We know form our problem that $f(x)=4-x^2$ and $g(x)=6x$ , so:
$(g-f)(x)=g(x)-f(x)$
$(g-f)(x)=6x-(4-x^2)$
$(g-f)(x)=6x-4+x^2$

Now, to find $(g-f)(3)$ , we just need to evaluate $(g-f)(x)$ at 3. In other words, we are going to replace $x$ with 3:
$(g-f)(x)=6x-4+x^2$
$(g-f)(x)=6(3)-4+(3)^2$

We can conclude that the correct answer is C.6(3) – 4 + 3^2

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3 years ago

Can someone please help me with this problem

zmey [24]

Answer:

I think that the answer is 83 but im not sure. I tried to solve it and i got 83. I hope its right.

5 0

3 years ago