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lesya692 [45]
4 years ago
7

I need help on 2,3, and 4

Mathematics
1 answer:
Shtirlitz [24]4 years ago
6 0
2: 0-4 and 15-19
3: rectangle, no, 17, 17, and because 15 + 16 + 17 + 18 + 19 = 85 and then 85 divided by 5 is 17. You get five from the numbers you add.
4: 1-15, 2-39, and 3- 54
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Rachel jogged a long a trail that was of 1/8 mile long . she jogged the 8 times. how meny miles trail did Rachel jog in all
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It's 1 mile. She ran an 8th if an mile. If the ran 1/8 of a mile 8 times, it adds up to 1 mile.
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C. 132.59<br> D. 134.24<br> Math question please help
timama [110]
OptionC is the answer..!!
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3 years ago
Write an equation of the form y = mx for the line shown below.
djyliett [7]

Answer:

y = -3x

Step-by-step explanation:

To get slope intercept, you divide both y values by both x values like this

\frac{y_2 - y_1}{x_2 - x_1}

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This will become \frac{-9}{3}

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7 0
3 years ago
The temperature was -5 degrees at 5:00 am. After 2 hours, the temperature increased by 39 degrees. What was the temperature at 7
Nesterboy [21]

Answer: 34 degrees

Step-by-step explanation:

The starting temperature was -5 degrees at 5am, and after two hours, the temperature was 34 degrees at 7am. The temperature increased by 39 degrees, how did we get this answer?

You add -5 and 39

-5 + 39 = 34

A tip for adding negatives:

When you get a problem similar to -5 + 39, you can actually flip them around if you need an easier understanding. So it would be 39 - 5. Both equations still equal 34 as long as you keep the values of each number!

5 0
3 years ago
In a rectangle FGHI, diagonals FH and GI intersect at E<br> What is the length of FH?
Hunter-Best [27]

Answer:

The length of \overline {FH} is;

D. 38 units

Step-by-step explanation:

The given parameters are;

The type of the given quadrilateral FGHI = Rectangle

The diagonals of the quadrilateral = \overline {FH} and \overline {GI}

The length of IE = 3·x + 4

The length of EG = 5·x - 6

We have from segment addition postulate, \overline {GI} = IE + EG

The properties of a rectangle includes;

1) Each diagonal bisects the other diagonal into two

Therefore,  \overline {FH} bisects \overline {GI}, into two equal parts, from which we have;

IE = EG

\overline {GI} = IE + EG

3·x + 4 = 5·x - 6

4 + 6 = 5·x - 3·x = 2·x

10 = 2·x

∴ x = 10/2 = 5

From which we have;

IE = 3·x + 4 = 3 × 5 + 4 = 19 units

EG = 5·x - 6 = 5 × 5 - 6 = 19 units

\overline {GI} = IE + EG = 19 + 19 = 38 units

\overline {GI} = 38 units

2) The lengths of the two diagonals are equal. Therefore, the length of segment \overline {FH} is equal to the length of segment \overline {GI}

Mathematically, we have;

\overline {FH} = \overline {GI} = 38 units

∴ \overline {FH} = 38 units.

5 0
3 years ago
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