3 years ago

3.90 is equivalent to how many tenths?

Mathematics

1 answer:

dlinn [17]3 years ago

4 0

Answer: 39 tenths

Divide 39÷10 and get 3.9

You might be interested in

Solve the equation.<br> Solve the equation.<br><br> q+59=16<br> q+5/9=1/6

Anika [276]

Answer:

I keep getting no solution

Step-by-step explanation:

3 0

3 years ago

Which statement best describes the interquartile range of this set of weights?

Arisa [49]

Answer:

Step-by-step explanation:

5 0

4 years ago

Read 2 more answers

5. Ms. Johnson has 50 students in Period 5. In

Citrus2011 [14]

Answer:

60% of the students are boys

8 0

3 years ago

Each of ten tickets is marked with a different number from 1 to 10 and put in a box. if you draw a ticket from the box, what is

Softa [21]

Answer:

7/10

Step-by-step explanation:

take 3, 2, 1 from the equation and your left with 7 numbers. Add those together you get 10. 7/10 is the probability that you will draw a number greater than 3

4 0

2 years ago

When individuals in a sample of 150 were asked whether or not they supported capital punishment, the following information was o

borishaifa [10]

Answer:

$\chi^2 = \sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

The expected values for all the categories is :

$E_i =\frac{150}{3}=50$

And then the statistic would be given by:

$\chi^2 = \frac{(40-50)^2}{50}+\frac{(60-50)^2}{50}+\frac{(50-50)^2}{50}=4$

And the best option would be:

b. 4

Step-by-step explanation:

For this problem we have the following observed values:

Yes 40 No 60 No Opinion 50

And we want to test the following hypothesis:

Null hypothesis: All the opinions are uniformly distributed

Alternative hypothesis: Not All the opinions are uniformly distributed

And for this case the statistic would be given by:

$\chi^2 = \sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

The expected values for all the categories is :

$E_i =\frac{150}{3}=50$

And then the statistic would be given by:

$\chi^2 = \frac{(40-50)^2}{50}+\frac{(60-50)^2}{50}+\frac{(50-50)^2}{50}=4$

And the best option would be:

b. 4

7 0

4 years ago