C according to my calculations
Answer:
E = 53.3 N/C
Explanation:
The charge of the sphere can be found by Gauss’ Law:
We will draw an imaginary spherical surface around the original sphere with radius 0.2 cm. The integral in the left-hand side is the area of this surface, therefore no need to take the integral. The right-hand side is equal to the total charge enclosed by this imaginary surface.
Now that we have found the charge of the sphere, we can now apply Gauss’ Law again to find the E-field 0.006 m from the center.
We will draw our second imaginary spherical surface with a radius 0.006 m.
The speed after 21 s is 18.9 m/s and the total time required for the train to reach a speed of 34 m/s is 14.4 s
<h3>
What is Speed ?</h3>
Speed is a distance travelled by a body per time taken. It is a scalar quantity and it is measured in m/s
Given that at Initially stationary, a train has a constant acceleration of 0.9 m/s2.
(a) What is its speed after 21 s?
- Acceleration a = 0.9 m/s²
Using v = u + at
Substitute all the parameters into the equation
v = 0 + 0.9 x 21
v = 18.9 m/s
(b) What is the total time required for the train to reach a speed of 34 m/s?
Let first calculate for total distance by using
v² = u² + 2as
34² = 18.9² + 2 × 0.9 × S
1156 = 357.21 + 1.8S
1.8S = 1156 - 357.21
1.8S = 798.79
S = 798.79 / 1.8
S = 443.8 m/s
v = u + at
34 = 21 + 0.9t
0.9t = 34 - 21
0.9t = 13
t = 13/0.9
t = 14.44s
Therefore, its speed after 21 s is 18.9 m/s and the total time required for the train to reach a speed of 34 m/s is 14.4 s
Learn more about Speed here: brainly.com/question/24739297
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Answer:
It will expand to a big red puff, and it will eventually settle down and turn into a white dwarf star, cooling down slowly by a trillion years.
Explanation: