The average useful power output of robot is 0.0001 W
The time taken by robot to lift bricks is 630000000 sec
Given:
work done by robot = 5.5 j
time taken to do the work = 12.0 hours
weight of bricks = 3500 kg
length of bricks = 1.8 m
To Find:
The average useful power output of robot is
The time taken by robot to lift bricks is
Solution: Useful power output means the electric or mechanical energy made available for use, exclusive of any such energy used in the power production process.
P = W/t
P = 5.5/12*3600
P = 0.0001 W
So, average useful power output of robot is 0.0001 W
t = W/P
W = mgh So t = mgh/P
t = 3500x10x1.8/0.0001
t = 630000000 sec
So, time taken by robot to lift bricks is 630000000 sec
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Complete question is;
The abc battery company claims that their batteries last 100 hours, on average. You decide to conduct a test to see if the company's claim is true. You believe that the mean life may be different from the 100 hours the company claims. you decide to collect data on the average battery life (in hours) of a random sample of n = 20 batteries. some of the information related to the hypothesis test is presented below:
Test of H0: μ = 100 versus H1: μ ≠ 100
Sample mean: 98.5
Std error of mean: 0.777
Assuming the life length of batteries is normally distributed, what is the p-value associated with this test?
Answer:
p-value = 0.00001
Explanation:
We are given;
Null hypothesis; H0: μ = 100
Alternative Hypothesis; H1: μ ≠ 100
Sample mean: x = 98.5
Standard error of mean; s = 0.777
To find the test statistic, we will use the formula;
t = (x - μ)/(s/√n)
t = (98.5 - 100)/(0.777/√20)
t = -1.5/0.1737
t = -8.64
Now, from online p-value from t-score calculator attached, using t = -8.64; DF = n - 1 = 20 - 1 = 19; two tail distribution;significance level of 0.05; we have;
The p-value = 0.00001
Answer:
Explanation:
The distance traveled by the sound wave between the beats of the wing is its wavelength, since it is defined as the distance traveled by a periodic disturbance that propagates in a cycle, is defined as:
Where v is the speed of sound and f the frequency of the wing beats
Answer:
Ff = 19.6 N
Explanation:
So since its saying whats the minimum F to move the block, we will use static friction (0.5).
We will use the equation for force of friction, which is Ff = uFn
Ff = (0.5)(4)(9.8)
Ff = 19.6 N
this is the minumum force needed to move the block, as that is the frictional force. You would need to apply a minimum force of 19.6 N to move the block