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Vikentia [17]
3 years ago
8

If you can show working thanks​

Mathematics
1 answer:
Phantasy [73]3 years ago
6 0

Answer:

Can't see the problem. Could you maybe take another picture. Thanks

Step-by-step explanation:

Peace

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What is the area of a parallelogram whose vertices are A(-12, 2), B6, 2). C(-2,-3), and D(-20, – 3)
guapka [62]

Answer:

-35

Step-by-step explanation:

This value of "a" is exactly the y-coordinate of the vertex of the parabola

y = x%5E2+%2B+4x++-+31.

To find it, complete the square:

x%5E2+%2B+4x++-+31 = %28x%2B2%29%5E2+-+4+-+31 = %28x%2B2%29%5E2+-+35.

So, this value of "a" is a = -35.

5 0
3 years ago
PLEASE HELP ASAP!!!! WILL GIVE BRAINLIEST TO CORRECT OR FIRST ANSWER!!!!!
Airida [17]
Your answer is 67.5. Hope this helps!
6 0
4 years ago
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A reading specialist wanted to estimate the mean word length, in number of letters, for an elementary school history textbook. T
Alika [10]

Answer:

Step-by-step explanation:

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7 0
3 years ago
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WIILL GIVE BRAINLIEST.
Dmitriy789 [7]

Answer:

C: The graph is not a function of x because the line y = 0 intersects the graph at two points.

Step-by-step explanation:

The line y = 0 will intersect the ellipse at the points, (-4 , 0) , (4 , 0)

6 0
3 years ago
A cone-shaped lampshade has a height of 18 cm and a slant height of 19.5 cm. Find the lateral surface area of the lampshade.
Aliun [14]

Check the picture below.

\textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \sqrt{19.5^2-18^2}=r\implies \sqrt{56.25}=r \\\\[-0.35em] ~\dotfill

\textit{lateral area of a cone}\\\\ LA=\pi r\sqrt{r^2+h^2}~~ \begin{cases} r=radius\\ h=height\\ \stackrel{slant~height}{\sqrt{r^2+h^2}}\\[-0.5em] \hrulefill\\ r=\sqrt{56.25} \end{cases}\implies \begin{array}{llll} LA=\pi \sqrt{56.25}\stackrel{slant~height}{(19.5)} \\\\\\ LA\approx 459.46~cm^2 \end{array}

5 0
2 years ago
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