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Colt1911 [192]
3 years ago
8

Please help me now I will mark you brainliest

Mathematics
1 answer:
omeli [17]3 years ago
6 0

Answer:

Out side the circle

Step-by-step explanation:

This is because the center is 0 and if the point 6, square root seven is on the circle that mean that as far as the circle goes on each side.

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Please help me please please
LenKa [72]

Answer:

1276.19553 m^{2}

Step-by-step explanation:

First, find height using Pythagoras thorem.

a=\sqrt{20^2+12.5^2}

a=15.61

Then use the formula to find the surface area of a cone.

π•12.5•(12.5+\sqrt{15.61^2+12.5^2})=1276.19553 m^{2}

6 0
3 years ago
A tree is 78 feet tall and grows 7 feet per year. A second tree is 111 feet tall and grows 4 feet per year.
Dahasolnce [82]
X = number of years
78 + 7x = 111 + 4x
-78 from both sides
7x = 33 + 4x
Subtract 4x from both sides
3x = 33
Divid both sides by 3
X= 11
In 11 years both trees will be the same height.
7 0
2 years ago
Read 2 more answers
What is the square root of 50?
Iteru [2.4K]

The square root of 50 is 7.071

5 0
3 years ago
Read 2 more answers
(a). Consider the parabolic function f(x) = ax² +bx+c, where a ±0, b and care constants. For what values of a, band c is f
ki77a [65]

Information about concavity is contained in the second derivative of a function. Given f(x) = ax² + bx + c, we have

f'(x) = 2ax + b

and

f''(x) = 2a

Concavity changes at a function's inflection points, which can occur wherever the second derivative is zero or undefined. In this case, since a ≠ 0, the function's concavity is uniform over its entire domain.

(i) f is concave up when f'' > 0, which occurs when a > 0.

(ii) f is concave down when f'' < 0, and this is the case if a < 0.

In Mathematica, define f by entering

f[x_] := a*x^2 + b*x + c

Then solve for intervals over which the second derivative is positive or negative, respectively, using

Reduce[f''[x] > 0, x]

Reduce[f''[x] < 0, x]

5 0
3 years ago
14. Which does not have a result of -21?
ikadub [295]

Answer:

B and D

Step-by-step explanation:

8 0
3 years ago
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