All categories

3 years ago

Р

Mathematics

1 answer:

melisa1 [442]3 years ago

6 0

Answer:

209 inches

Step-by-step explanation:

95% of 220 is 209 inches so therefor it would be 209 inches.

You might be interested in

The sum of two consecutive numbers is -171. find the value of a greater number

Vadim26 [7]

Answer: 103

Step-by-step explanation:Find the two numbers. Now solve for "x" to find your first number, and add 1 to find the consecutive number. Remember to replace these two values in the original equation to verify they work. In other words, the sum of the first number and 3 times the second number must equal 103.

IF YOU CAN GIVE BRAINLYIST THAT WOULD BE NICE THX. :)

8 0

3 years ago

Pleasaaaaseee answer the all for BRAINLEST answer and thanks

seropon [69]

For the first one are you looking for g? or the steps

7 0

3 years ago

Prove that sequence an = (3^n)/(2n)! is monotone

krek1111 [17]

When $n=1$ , you have $a_1=\dfrac3{2!}=\dfrac32$ .

When $n=2$ , you have $a_2=\dfrac{3^2}{4!}=\dfrac38$ .

Clearly, $a_1>a_2$ .

Assume $a_k$ . Now when $n=k+1$ , you have

$a_{k+1}=\dfrac{3^{k+1}}{(2k+2)!}=\dfrac3{(2k+2)(2k+1)}\times\dfrac{3^k}{(2k)!}=\dfrac3{(2k+2)(2k+1)}a_k$

Therefore by induction the sequence is monotone (decreasing).

5 0

3 years ago

Can anyone answer this >?

Alona [7]

Answer:

see explanation

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + b

where m is the slope and b the y- intercept

7 0

3 years ago

Read 2 more answers

A manager is comparing wait times for customers in a coffee shop based on which employee is

anyanavicka [17]

Using the t-distribution, as we have the standard deviation for the sample, it is found that there is a significant difference between the wait times for the two populations.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, we test if there is no difference, that is:

$H_0: \mu_A - \mu_B = 0$

At the alternative hypothesis, it is tested if there is difference, that is:

$H_1: \mu_A - \mu_B = 0$

<h3>What are the mean and the standard error of the distribution of differences?</h3>

For each sample, we have that:

$\mu_A = 73, s_A = \frac{2}{\sqrt{100}} = 0.2$

$\mu_B = 74, s_B = \frac{4}{\sqrt{100}} = 0.4$

For the distribution of differences, we have that:

$\overline{x} = \mu_A - \mu_B = 73 - 74 = -1$

$s = \sqrt{s_A^2 + s_B^2} = \sqrt{0.2^2 + 0.4^2} = 0.447$

<h3>What is the test statistic?</h3>

It is given by:

$t = \frac{\overline{x} - \mu}{s}$

In which $\mu = 0$ is the value tested at the null hypothesis.

Hence:

$t = \frac{\overline{x} - \mu}{s}$

$t = \frac{-1 - 0}{0.447}$

$t = -2.24$

<h3>What is the p-value and the decision?</h3>

Considering a one-tailed test, as stated in the exercise, with 100 - 1 = 99 df, using a t-distribution calculator, the p-value is of 0.014.

Since the p-value is less than the significance level of 0.05, it is found that there is a significant difference between the wait times for the two populations.

More can be learned about the t-distribution at brainly.com/question/16313918

8 0

2 years ago