Using the cosine ratio, the value of AD in the diagram is: 2√3π in.
<h3>How to Apply the Cosine Ratio?</h3>
If we have the following given in a right triangle like triangle ADC in the diagram:
AC = 4π (hypotenuse)
AD = ? (adjacent side)
The cosine ratio, CAH would be applied, which is:
Cos 30 = adjacent/hypotenuse
Cos 30 = AD/4π
AD = cos 30 × 4π = √3/2 × 4π [cos 30 = √3/2]
AD = 2√3π in.
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Answer:c 10
Step-by-step explanation:u90k9i0iol
I think the answer is -15. Hope I helped
Answer:
Coordinates of E is (-2,7)
Step-by-step explanation:
Midpoint = ((x1+x2)/2,(y1+y2)/2)
xK = (xW + xE)/2 => xE = 2xK - xW = 2(0) - 2 = -2
yK = (yW + yE)/2 => yE = 2yK - yW = 2(3) - (-1) = 7
Well 66 is 66 and 2/3 is 66.6 repeating so 66 <span />