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Novay_Z [31]
3 years ago
12

Evaluate for x=2 and y=3: x^2y^-3/x^-1y

Mathematics
1 answer:
Artemon [7]3 years ago
4 0

Answer:

8/81

Step-by-step explanation:

It's most efficient to simplify the quotient algebraically before inserting the values of the variables x and y.  

The given expression reduces to x³ / y^4.

Substituting 2 for x and 3 for y, we get:

 (2)³           8

--------- = ---------- (Agrees with first given possible answer)

 (3)^4         81

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If f(x) = x^2 - 4x + 1, find the range of f(x).<br><br> {y: y ≥ -3}<br> {y: y ≥ 13}<br> all reals
Tomtit [17]
Hello : 
y= <span>x² - 4x + 1
calculate : x 
y = (x²-4x+4)-4+1
y+3 = (x-2)²
x exist : if   y+3 </span><span>≥ 0
y </span><span>≥ -3
the range is : </span><span>{y: y ≥ -3}</span>
8 0
3 years ago
Find the slope of the described line by x - 6y = -12​
Simora [160]

Answer:

Slope <em>m</em> = 1/6

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Equality Properties

<u>Algebra I</u>

Standard Form: Ax + By = C

Slope-Intercept Form: y = mx + b

  • m - slope
  • b - y-intercept

Step-by-step explanation:

<u>Step 1: Define</u>

x - 6y = -12

<u>Step 2: Rearrange</u>

<em>Find slope-intercept form.</em>

  1. Subtract <em>x</em> on both sides:                    -6y = -x - 12
  2. Divide -6 on both sides:                      y = 1/6x + 2

<u>Step 3: Break Function</u>

<em>Identify Parts.</em>

Slope <em>m</em> = 1/6

y-intercept <em>b </em>= 2

8 0
3 years ago
What is the slope of the line described below? Y-9=15(x-5)
Ksivusya [100]

slope = 15

the equation of a line in ' point- slope form ' is

y - b = m(x - a) → ( where m is the slope and (a, b) a point on the line)

y - 9 = 15(x - 5) is in this form

thus slope = m = 15



3 0
4 years ago
Simplify the expression :)<br> pls help
Ad libitum [116K]

Answer:

c^6 d^18 x^3..........

8 0
3 years ago
(4y^2-3y+2)+(5y+12y-4)-(13y^2-6y+20)
Andrews [41]

Answer:

-(9 y^2 - 20 y + 22) or if you need y = 10/9 + (7 i sqrt(2))/9 or y = 10/9 - (7 i sqrt(2))/9

Step-by-step explanation:

Simplify the following:

-(13 y^2 - 6 y + 20) + 4 y^2 + 12 y + 5 y - 3 y - 4 + 2

Grouping like terms, -(13 y^2 - 6 y + 20) + 4 y^2 + 12 y + 5 y - 3 y - 4 + 2 = -(13 y^2 - 6 y + 20) + 4 y^2 + (-3 y + 5 y + 12 y) + (2 - 4):

-(13 y^2 - 6 y + 20) + 4 y^2 + (-3 y + 5 y + 12 y) + (2 - 4)

-3 y + 5 y + 12 y = 14 y:

-(13 y^2 - 6 y + 20) + 4 y^2 + 14 y + (2 - 4)

2 - 4 = -2:

-(13 y^2 - 6 y + 20) + 4 y^2 + 14 y + -2

-(13 y^2 - 6 y + 20) = -13 y^2 + 6 y - 20:

-13 y^2 + 6 y - 20 + 4 y^2 + 14 y - 2

Grouping like terms, 4 y^2 - 13 y^2 + 14 y + 6 y - 20 - 2 = (-13 y^2 + 4 y^2) + (6 y + 14 y) + (-20 - 2):

(-13 y^2 + 4 y^2) + (6 y + 14 y) + (-20 - 2)

4 y^2 - 13 y^2 = -9 y^2:

-9 y^2 + (6 y + 14 y) + (-20 - 2)

6 y + 14 y = 20 y:

-9 y^2 + 20 y + (-20 - 2)

-20 - 2 = -22:

-9 y^2 + 20 y + -22

Factor -1 out of -9 y^2 + 20 y - 22:

Answer: -(9 y^2 - 20 y + 22)

______________________________________________

Solve for y:

-9 y^2 + 20 y - 22 = 0

Divide both sides by -9:

y^2 - (20 y)/9 + 22/9 = 0

Subtract 22/9 from both sides:

y^2 - (20 y)/9 = -22/9

Add 100/81 to both sides:

y^2 - (20 y)/9 + 100/81 = -98/81

Write the left hand side as a square:

(y - 10/9)^2 = -98/81

Take the square root of both sides:

y - 10/9 = (7 i sqrt(2))/9 or y - 10/9 = -(7 i sqrt(2))/9

Add 10/9 to both sides:

y = 10/9 + (7 i sqrt(2))/9 or y - 10/9 = -(7 i sqrt(2))/9

Add 10/9 to both sides:

Answer: y = 10/9 + (7 i sqrt(2))/9 or y = 10/9 - (7 i sqrt(2))/9

4 0
3 years ago
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