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Novay_Z [31]
3 years ago
12

Evaluate for x=2 and y=3: x^2y^-3/x^-1y

Mathematics
1 answer:
Artemon [7]3 years ago
4 0

Answer:

8/81

Step-by-step explanation:

It's most efficient to simplify the quotient algebraically before inserting the values of the variables x and y.  

The given expression reduces to x³ / y^4.

Substituting 2 for x and 3 for y, we get:

 (2)³           8

--------- = ---------- (Agrees with first given possible answer)

 (3)^4         81

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A candy store makes a 9-pound mixture of gummy candy, jelly beans, and hard candy. The cost of gummy candy is $2.00 per pound, j
Musya8 [376]

Let

x--------> the amount of gummy candy in pounds

y--------> the amount of jelly beans in pounds

z-------->  the amount of hard candy in pounds

we know that

x+y+z=9 --------> equation 1

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x=2y --------> equation 3  

Substitute equation 3 in equation 1 and equation 2

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using a graphing tool ------> Solve the system of equations

see the attached figure

the solution is the point (3,2)

z=3\ pounds\\y=2\ pounds

<u>Find the value of x</u>

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x=2*2=4\ pounds

therefore

<u>the answer is</u>

the amount of gummy candy is 4\ pounds

the amount of jelly beans is 2\ pounds

the amount of hard candy is 3\ pounds

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3 years ago
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Answer:

66

Step-by-step explanation:

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                                     = 66                                              =66

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3 years ago
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