<u>Given:</u>
# Molecules of NaOH = 1.50 * 10²³
<u>To determine:</u>
The # moles of NaOH present in the given molecules
<u>Explanation:</u>
By definition:
1 mole of NaOH corresponds to Avogadro's number i.e. 6.023*10²³ molecules
Therefore the moles of NaOH corresponding to the given molecules would be = 1.50*10²³ molecules NaOH * 1 mole NaOH/6.023*10²³ molecules NaOH
= 0.249 moles
Ans: 0.249 moles of NaOH
Answer:
polymerization
Explanation:
Student is explaining the process of formation of a polymer and the process is called polymerization.
Polymer is made up of joining repeating units. The repeating units are called monomers.
Properties of the polymer is determined by the structure of monomer molecule.
For example, consider a well-known polymer Teflon.is made by the polymerization of tetrafluoroethane.
Thus, the student is explaining polymerization.
Answer:
Highest boiling point - 0.43 m Urea
Second highest boiling point - 0.20 m NiSO4
Third highest boiling point - 0.19 m NH4I
Lowest boiling point - 0.17 m NH4NO3
Explanation:
We know that;
ΔT = kb m i
Where;
ΔT = boiling point elevation
kb = boiling point constant
m = molality of the solution
i = Van't Hoff factor
For NiSO4 , NH4I and NH4NO3 , the Van't Hoff factor, i = 2
But for Urea, the Van't Hoff factor, i = 1
We also have to consider both the values of the molality and Van't Hoff factor , knowing that a higher molality and a higher Van't Hoff factor leads to a higher ΔT and consequently a higher boiling point.
This facts above account for the arrangement of substances shown in the answer.
Answer:
is reduced in the reaction
Explanation:
The given reaction is
The oxidation number of is changed from
And The oxidation number of is changed from
Hence, is oxidized and is reduced