I would say 1 would be the least possible remainder...
11/5 = 2 remainder 1
21/5 = 4 remainder 1
31/5 = 3 remainder 1
and since ur dealing with positive integers (whole numbers), 1 is gonna be the smallest
Answer:
352 students
Step-by-step explanation:
Given
See attachment for table
Required
Attendance of students in this year's show
First, we calculate the mean of the table
So, we have:
Multiply the mean by the total students
Answer:
The midpoint is (4,3)
Step-by-step explanation:
I attached the midpoint formula.
<u>( -1 + 9 )</u> <u>( 4 + 2 )</u>
2 2
8 / 2 = 4 6 / 2 = 3
(4,3)