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Rudik [331]
3 years ago
14

The slope of the line segment above is True False

Mathematics
2 answers:
jolli1 [7]3 years ago
7 0

Answer:False

Step-by-step explanation:

Because when you go up and you subtract that numbers you don't get the number you need

Bezzdna [24]3 years ago
4 0

Answer:

False

Step-by-step explanation:

then again I don't understand graphs and this one doesn't make sense at all cause first of all its in quadrant 2 so everything is positive... my apologies if I didn't help

<3 Enjoy,

    Dea

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Find the measure of unknown angle​
Lemur [1.5K]

Answer:

Step-by-step explanation:

z = 102 degree (opposite angles of a parallelogram are equal)

z + x + 34 = 180 degree 9sum of adjacent angles of a parallelogram is 180 degree)

102 + x + 34 = 180

x = 180 - 136

x = 44 degree

y + 102 + x = 180 degree (sum of interior angles of a triangle is 180 degree)

y + 102 + 44 = 180

y = 180 - 146

y = 34 degree

3 0
3 years ago
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Find the length of the legs of a right triangle if the legs are the same length and
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Answer:

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Matt have 2 cookies, while christine have 2 more than matt how many cookies will they have if the add them altogethe?.
mojhsa [17]

Answer:

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3 years ago
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During the summer, Shane earns $450 every two weeks from being a lifeguard. He saves $125 from each paycheck. According to the t
DanielleElmas [232]

Answer:

5 to 18 ; 1 to 225

Step-by-step explanation:

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4 0
4 years ago
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Let g (x) = 3x+2 and f (x) = x-2 / 3 find the value. g (f(2))
Romashka [77]

Answer: OPTION C.

Step-by-step explanation:

In order to solve the given exercise, you can follow these steps:

1. Given the following function f(x):

f(x)=\frac{x-2}{3}

You must substitute x=2 into the function f(x). Then:

f(2)=\frac{(2)-2}{3}

2. Evaluating, you get:

f(2)=\frac{0}{3}\\\\f(2)=0

3. Now, the next step is to substitute f(2)  into the function g(x):

g (x) = 3x+2\\\\g (f(2)) = 3(0)+2

4. Finally, evaluating, you get the following result:

g (f(2)) = 0+2\\\\g (f(2)) =2

You can identify that it matches with the Option C.

3 0
4 years ago
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