Answer:
Step-by-step explanation:
5c^5-c+c^5+7c-2
add like terms
=6c^5-c+7c-2
subtract like terms
=6c^5+6c-2
=2(3c^5+3c-1)
33,050
33,000
32,100
32,082
M = T - R
Add R on both sides.
M + R = T - R + R
-R+R=0 so the resulting equation would be
M + R = T
The answer is T = M + R
The sum of 3.0478 and 4.92 is , which have 5 significant digits.
<u>Step-by-step explanation:</u>
We have , and . The significant digits of a number are digits that includes all digits except:
- All leading zeros. For example, "013" has two significant figures: 1 and 3;
- Trailing zeros when they are merely placeholders to indicate the scale of the number and ,
- Spurious digits introduced, for example, by calculations carried out to greater precision than that of the original data, or measurements reported to a greater precision than the equipment supports.
Here and with significant digit rules . Now, Sum of both numbers =
⇒Sum of both numbers =
⇒Sum of both numbers =
∴ The sum of 3.0478 and 4.92 is , which have 5 significant digits.