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3 years ago

Which expression is not equivalent to 3x-2

Mathematics

1 answer:

Lemur [1.5K]3 years ago

6 0

Answer: Let's simplify step-by-step.

3x−2

There are no like terms.

So it going to be the same, =3x-2

Step-by-step explanation: hope you understand

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A total of 488

zavuch27 [327]

Idk.. If you divide 488 by 3 you will have your answer.
Its easy math.

5 0

4 years ago

5. AC bisects Angle BAD. Find the measure of angle BAC.

Diano4ka-milaya [45]

60 12×5 is 60 all you really need to look at is the 12

3 0

4 years ago

Question:

aivan3 [116]

Answer:

part A) The scale factor of the sides (small to large) is 1/2

part B) Te ratio of the areas (small to large) is 1/4

part C) see the explanation

Step-by-step explanation:

Part A) Determine the scale factor of the sides (small to large).

we know that

The dilation is a non rigid transformation that produce similar figures

If two figures are similar, then the ratio of its corresponding sides is proportional

Let

z ----> the scale factor

$\frac{CB}{C'B'}=\frac{CD}{C'D'}=\frac{BD}{B'D'}$

The scale factor is equal to

$z=\frac{CB}{C'B'}$

substitute

$z=\frac{4}{8}$

simplify

$z=\frac{1}{2}$

Part B) What is the ratio of the areas (small to large)?

Area of the small triangle

$A=\frac{1}{2}(2)(4)=4\ units^2$

Area of the large triangle

$A=\frac{1}{2}(4)(8)=16\ units^2$

ratio of the areas (small to large)

$ratio=\frac{4}{16}=\frac{1}{4}$

Part C) Write a generalization about the ratio of the sides and the ratio of the areas of similar figures

In similar figures the ratio of its corresponding sides is proportional and this ratio is called the scale factor

In similar figures the ratio of its areas is equal to the scale factor squared

4 0

4 years ago

-4 = -2 + 2x What is the answer to this

mamaluj [8]

X=-1
I hope this helps :)

8 0

3 years ago

Read 2 more answers

Find an equation equivalent to r = 10 sinθ in rectangular coordinates

Flura [38]

Answer:

$x^{2} + y^{2} - 10\cdot y = 0$

Step-by-step explanation:

The following expressions are used to transform from polar into rectangular form:

$r = \sqrt{x^{2}+y^{2}}$

$\sin \theta = \frac{y}{\sqrt{x^{2}+y^{2}}}$

Now, the variables are substituted and equation is finally simplified:

$\sqrt{x^{2}+y^{2}} = 10\cdot \frac{y}{\sqrt{x^{2}+y^{2}} }$

$x^{2}+y^{2} = 10\cdot y$

The equivalent equation in rectangular coordinates is:

$x^{2} + y^{2} - 10\cdot y = 0$

8 0

3 years ago