Given problem;
Number of quarters in $40;
To solve this problem;
- <u>Convert the dollar value to cents</u>;
100cents = $1
In $40, we would have; 40 x 100 = 4000cents
So, divide 4000cents by 25 to obtain the number of quarters in that amount of dollars;
Number of quarters = 
= 160
So there are 160 quarters in $40
Considering the sequences given, the first number that appears in both sequences is given by: 45.
<h3>What numbers appear in the first sequence?</h3>
The rule is multiply by 3 starting from 5, hence the numbers are:
(5, 15, 45, 135, ...).
<h3>What numbers appear in the second sequence?</h3>
The rule is add 9 starting from 18, hence the numbers are:
(18, 27, 36, 45, ...).
45 is the first number that appeared in both sequences.
More can be learned about sequences at brainly.com/question/6561461
#SPJ1
Where is the graph show the graph
Answer:
691.241
Step-by-step explanation:
678.901
+12.340
Add a zero at the end.
Answer:
D. It has a single solution: x=-3, y= 26.
Step-by-step explanation:
3x + y=17
Subtract 3x so it is in y=mx+b form. So now it is y= -3x +17
Now plug in
x + 2 (-3x+17) = 49
x + -6x + 34 = 49 (distribute)
-5x = 15 (combine the x terms and subtract 34 on both sides)
x = -3 (divide -5 on both sides to get x alone)
now plug in x into any other equation to get y
x + 2y = 49
-3 + 2y = 49
2y = 52 (add 3 on both sides)
y = 17 (divide 2 on both sides to get y alone)
(-3, 26)
