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3 years ago

Please help me solve this question

Mathematics

1 answer:

pav-90 [236]3 years ago

7 0

3365900000 : thats the answer

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Plzz help its only 1 question!!!

andrew11 [14]

Answer:

D is correct

rost beef sandwich=7$

turkey sandwich=5$

Step-by-step explanation:

8 0

3 years ago

Solve for q. 3(q − 7) = 27 q =

Whitepunk [10]

Answer:

The answer is, q = 16.

Step-by-step explanation:

1) Divide both sides by 3.

$q - 7 = \frac{27}{3}$

2) Simplify 27/3 to 9.

$q - 7 = 9$

3) Add 7 to both sides.

$q = 9 + 7$

4) Simplify 9 + 7 to 16.

$q = 16$

Therefor, the answer is q = 16.

8 0

3 years ago

Read 2 more answers

The diameter of a cone is 1.5 meters, the height is 1.5 times the radius, what is the volume?

seropon [69]

Answer:

.66 cu. meters

Step-by-step explanation:

volume for cone is V=1/3 x TT x r^2 x height

TT (pi) is 3.14

radius is 1/2 of diameter (1/2 x 1.5 = .75 )

height is 1.5 x radius (1.5 x .75 = 1.125)

V= 1/3 x 3.14 x .75^2 x 1.125

V= .66 cu. meters

6 0

2 years ago

Complete the comparison: 2+7>? a. 9+4 b. 7+3 c. 10-2 d. 8+2

Zina [86]

The answer is c because 2+7=9 and 10-2=8 and 9 is greater than 8 so 2+7>10-2

5 0

3 years ago

Y=arccos(1/x) Please help me do them all! I don’t know derivatives :(

Stells [14]

Answer:

$f(x) = {sec}^{ - 1} x \\ let \: y = {sec}^{ - 1} x \rightarrow \: x = sec \: y\\ \frac{dx}{dx} = \frac{d(sec \: y)}{dx} \\ 1 = \frac{d(sec \: y)}{dx} \times \frac{dy}{dy} \\ 1 = \frac{d(sec \: y)}{dy} \times \frac{dy}{dx} \\1 = tan \: y.sec \: y. \frac{dy}{dx} \\ \frac{dy}{dx} = \frac{1}{tan \: y.sec \: y} \\ \frac{dy}{dx} = \frac{1}{ \sqrt{( {sec}^{2} \: y - 1}) .sec \: y} \\ \frac{dy}{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} } \\ \therefore \frac{d( {sec}^{ - 1}x) }{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} } \\ \frac{d( {sec}^{ - 1}5x) }{dx} = \frac{1}{ |5x | \sqrt{25 {x }^{2} - 1} }\\\\y=arccos(\frac{1}{x})\Rightarrow cosy=\frac{1}{x}\\x=secy\Rightarrow y=arcsecx\\\therefore \frac{d( {sec}^{ - 1}x) }{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} }$

4 0

3 years ago