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love history [14]
3 years ago
7

What is the starting point of the quadratic function defined by y=-2x2-25x+10?

Mathematics
1 answer:
horrorfan [7]3 years ago
3 0

Step-by-step explanation:

y=-2x²-25x+10

=x²+25/2x-5

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(08.03) Consider the following pair of equations:
Arlecino [84]
Combine two sequence, 3x+3=x-1. then, you can know x=-2. and put x value to any sequence. then, y= -3.
answer:(-2,-3)
5 0
4 years ago
A circle has a radius of 3. An arc in this circle has a central angle of 60. What is the length of the arc ?
Mashutka [201]
This is the formula:

Arc length = 2(3.14)(3)(60/360)

18.84(60/360)

18.84 x 0.16 = 3

The length of the arc = 3

4 0
3 years ago
Which inequality is represented by the graph? y≥35x−1.5 y≤35x−1.5 y<35x−1.5 y>35x−1.5
Setler79 [48]

Answer:

y > 0.6x - 1.5

Step-by-step Explanation:

We need two points, to get to the equation of the graph.

Since we've got the following equation for two points (x1, y1), (x2, y2):-

\boxed{ \mathsf{ \red{y - y_{1} =  \frac{y_{2} - y_{1}}{x_{2} - x_{1}} (x - x_{1})  }}}

okay soo

I found two points that lie on this graph, not on the shaded region but yeah the dotted line which defines the graph.

one point is <u>(0, -1.5)</u> which lies on the y axis(the point where the dotted line touches the y axis)

other point is <u>(2.5, 0)</u> and this lies on the x axis

placing these points in the place of (x1, y1) and (x2, y2) in the above mentioned equation

\mathsf{\implies y - ( - 1.5) =  \frac{0 -( - 1.5)}{2.5 -0 } (x -0 )}

you can take any one as (x1, y1) or (x2, y2).

so upon solving the above equation we get

\mathsf{\implies (y  +  1.5) =  \frac{0  +  1.5}{2.5  } (x  )}

\mathsf{\implies y  +  1.5 =  \frac{ 1.5}{2.5  } x  }

\mathsf{\implies y  +  1.5 =  \frac{ \cancel{1.5}\:\:{}^3}{\cancel{2.5}\:\:{}^5 } x  }

\mathsf{\implies y  +  1.5 =  \frac{ 3}{5 } x  }

multiplying both sides by 5

\mathsf{5y + 7.5 = 3x}

okay so this is the required equation of the dotted line

now we'll find the inequality

for this check whether the origin (0,0) lies under the shaded region or not

in this case it does

so

replacing x and y with 0

\mathsf{\implies5(0) + 7.5 = 3(0)}

\mathsf{\implies0 + 7.5 = 0}

this is absurd, 7.5 is not equal to 0 so we're gonna replace that equals sign with that of inequality

7.5 is greater than 0! so,

\mathsf{\implies7.5 > 0}

this goes for the whole equation, since we didnt swap any thing from left to right side of the equation or vice versa we can use this sign, to obtain the required inequality

\mathsf{5y + 7.5 > 3x}

dividing this inequality by 5, since there's no co-efficient in front of y in the given answers

we get

y + 1.5 > 0.6x

taking 1.5 to the RHS

<h3>y > 0.6x - 1.5 </h3>

that is the last option

5 0
3 years ago
Is 25 possible solution to the following inequality?<br><br> 100 &lt; 4x
ddd [48]

Answer:

No

Step-by-step explanation:

100 < 4x

Divide each side by 4

100/4 < 4x/4

25 < x

It states is must be less than

But 25 is equal to 25, so it cannot be a solution

7 0
3 years ago
If (x+yi)+2(3x-y)+4i-0;then the value of x and y is​
lianna [129]

Answer:

X=0 and Y= 4(2i-1)/5

Step-by-step explanation:

Here is my solution, assuming that the equation equals 0. For y, just remember the definition of complex numbers and multiply by its conjugate.

5 0
3 years ago
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