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pentagon [3]
3 years ago
7

What happens if we nuke a city?

Physics
2 answers:
nignag [31]3 years ago
3 0
The shadow would subsequently drop the temperature in the city, forcing warmer air to rush in and violently destroy countless buildings. There would also be “black rain,” which would be the radioactive ash and dust that would liquify and pour down on the city and we would all die.
irga5000 [103]3 years ago
3 0

Answer:

Those who survived the bomb may become deaf or blind, as well as suffer catastrophic burns and injuries. Even people who were not seriously injured could become trapped within a structure or unable to navigate through the wreckage.

Explanation:

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A loudspeaker having a diaphragm that vibrates at 910 Hz is traveling at 75.0 m/s directly toward a pair of holes in a very larg
Alina [70]

To solve this problem we need to apply doppler equation,

Our values are:

f_0 = 910Hz\\c = 75m\\v=344m/s\\\theta= 12.9\°\\

Doppler equation is given by,

f= \frac{v}{v-c} f_0

Substituting,

f= \frac{344}{344-75}*910

f = 1163Hz

\lambda = \frac{344}{1163}

Wavelenght is equal to,

\lambda = \frac{c}{f}

\lambda = 0.2956

We can now find the distance by,

d= \frac{1}{2}\frac{\lambda}{sin\theta}

d=\frac{1}{2}\frac{0.2956}{sin(12.9)}

d= 0.66m

b) We can find at what angles would sound first cancel through the same equation of wavelenght,

\lambda = \lambda{c}{f} = \frac{344}{1163}

d* sin\theta = \frac{1}{2}*\lambda

\theta = arcsin( 0.5*(344/1163)/0.66)=12.94\°

5 0
3 years ago
The doppler effect is used to determine?
Korolek [52]
Uhh it is used to detirmine heat

7 0
3 years ago
Read 2 more answers
"Find the total weight of an 18-ft3 tank of oxygen if the oxygen is pressurized to 184 psia, the tank itself weighs 150 lbf, and
Fiesta28 [93]

Answer:

Explanation:

1 psi = 6894.76 Pa

P = 184 psi = 12.686 x 10⁵ Pa .

Temperature T = 95⁰F = 35⁰C= 308 K

volume V = 18 ft³ = 18 x 0.0283168 m³

= .51 m³

From the gas law

PV/RT = n where n is mole of gas

= 12.686 x 10⁵ x  .51  / 8.31 x 308

= 252.78 gm mole

= 252.78 x 32 gm

= 8.08896 kg

= 2.20462 x 8.08896 lb

= 17.833 lb

= 17.833 / 32 lbf

= .5573 lbf

weight of tank = 150 lbf

Total weight = 150 + .5573

= 150.5573 lbf .

7 0
3 years ago
A pump lifts 400 kg of water per hour a height of 4.5 m .
nasty-shy [4]

Answer:

Power = Work / Time

P = 400 kg * 9.8 m/s * 4.5 m / 3600 sec = 4.9 J/s = 4.9 Watts

Also, 4.9 Watts / (746 Watts / Horsepower) = .0066 Hp

6 0
3 years ago
How do tou find the acceleration of a car between two points on a velocity-time variation graph
Bezzdna [24]
The magnitude of acceleration is

(change in speed) divided by (time for the change) .

Between the two points on the graph ...

-- Find the change in speed. (usually the y-axis)
-- Find the change in time. (usually the x-axis)

Divide (change in time) by (change in speed) between the two points.
That quotient is the average magnitude of acceleration during that time.

If the graph happens to be a straight line, then the magnitude of acceleration
is just the slope of the line.
3 0
4 years ago
Read 2 more answers
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