Answer:
y=7 and x=-8
Step-by-step explanation:
Isolate x in the first equation:
10x=-17-9y
x=(-17-9y)/10
Substitute into the second equation:
7*((-17-9y)/`10)+10y=14
-119/10+37y/10=14
-119+37y=140
37y=259
y=7
Putting this into the first equation, we get that x=-8
Vertex:(-1,-4)
Concavity: up
Domain: -♾< x < ♾
Range: y > (or equal to) -4
Roots: (-3,0) (1,0)
Factors: (x + 3) (x - 1)
Equation: x^2 + 2x - 3
Answer:
21+/-sqrt(253)=x
So one value for x is 21+sqrt(253)
and another is 21-sqrt(253)
Problem:
Given (21,7) and (x,1), find all x such that the distance between these two points is 17.
Step-by-step explanation:
Change in x is x-21
Change in y is 7-1=6
distance^2=(change in x)^2+(change in y)^2
17^2=(x-21)^2+(6)^2
289=(x-21)^2+36
Subtract 36 on both sides:
289-36=(x-21)^2
253=(x-21)^2
Take square root of both sides:
+/-sqrt(253)=x-21
Add 21 on both sides:
21+/-sqrt(253)=x
False, because if you do the grouping method, it would be (x+8) (x - 4).
Answer:
Step-by-step explanation:
slope = m = (10-7)/4+3) = 3/7
y=3x/7+b
plug in either point to solve for b=y intercept
10=(3/7)/4+b =12/7+b
b =10-12/7 = 58/7
y=3x/7 + 58/7 or
eliminate the fractions
multiply by 7 to get
7y=3x + 58