The magnitude of the force on the left-hand pole of the thin flexible gold chain of uniform linear density with a mass of 17.1 and, hangs between two 30.0 cm long vertical sticks, which are a distance of 30.0 cm apart will be, 0.167N.
To find the correct answer, we have to know more about the Basic forces that acts upon a body.
<h3>What is force and which are the basic forces that acts upon a body?</h3>
- A push or a pull which changes or tends to change the state or rest, or motion of a body is called Force.
- Force is a polar vector as it has a point of application.
- Positive force represents repulsion and the negative force represented attraction.
- There are 3 main forces acting on a body, such as, weight mg, normal reaction N, and the Tension or pulling force.
<h3>How to solve the problem?</h3>
- We have given that, the gold chain hangs between the vertical sticks of 30cm and the horizontal distance between then is 30cm.
- From the given data, we can find the angle (in the free body diagram, it is given as θ).
- From the free body diagram given, we can write the balanced equations of total force along y direction as,
- From the free body diagram given, we can write the balanced equations of total force along x direction as,
Thus, we can conclude that, the magnitude of force on the left-hand pole will be 0.167N.
Learn more about the Basic forces that acts upon a body here:
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Answer:
Doppler effect changes the wavelength of the light emitted, depending upon whether source is moving away or coming towards the observer(detector).
Explanation:
Doppler effect in light is actually a relativistic effect but somewhat similar to the one which happens in sound waves.
When the source is moving away from the detector, the wavelength of the light emitted from the source appears to be increased as seen by the detector, as a result the frequency decreases(we know that frequency of light= speed of light/wavelength of light. Here speed of light is constant and frequency of light is inversely proportional to its wavelength)
Due to this decrease in frequency the light emitted from the source appears more red, since red color is on low frequency side in the electromagnetic spectrum.
Similarly for the source moving towards the detector, the wavelength appears to be decreased, thereby resulting in increase in frequency and the source appears blue. The shift in frequency is known as doppler shift.
The shift in frequency when the source is moving away is known as redshift and the one where the source is moving towards detector is known as blueshift
Answer:
a. 1715 N b. 2401 N
Explanation:
Let F = force due to calf muscle, F' = force due to tibia and N = force due to ground = weight of man = mg where m = mass of man = 70 kg and g = acceleration due to gravity = 9.8 m/s².
a. Magnitude of the forces exerted on the foot by the muscle
Since the force due to the calf muscle is 6.0 cm behind the ankle joint and the normal force due to the ground is 15.0 cm in front of the ankle joint and the force due to the tibia is at the ankle joint, taking moments about the ankle joint,
F × 6 cm + F' × 0 cm = N × 15 cm
6F = 15N = 15mg
F = 15mg/6
= 15 × 70 kg × 9.8 m/s²/6
= 1715 N
b. Magnitude of the forces exerted on the foot by the tibia
Taking moments about the calf muscle force, we have
F × 0 cm + F' × 6 cm = N × (15 cm + 6 cm)
6F' = 21N = 21mg
F' = 21mg/6
= 21 × 70 kg × 9.8 m/s²/6
= 2401 N
Newton I think. I could be wrong