Answer: 105
Step-by-step explanation:
28% es 0.28 en decimal
28% de 375 es 375 x 0.28
375 x 0.28 = 105
Are you supposed to multiply these? If so your answer would be (5x*x^2) + (5x*-x) + (5x*-7). This comes out to 5x^3 - 5x^2 - 35x. Hope this helps!
14+2 is 16 for example
Just add 2 until you get to the number of rows you need if you need more help just ask
Answer:
Angle between vectors u and v: 26.56 degrees
Step-by-step explanation:
I just recently did this question, so here's my response and hopefully that helps you:
Vector u is <-3,-4> and vector v is <-2,-1>. To find the angle between the two vectors, you first need to find their dot product. This means that u*v = <-3,-4> * <-2,-1> = (-3)(-2) + (-4)(-1) = 6 + 4 = 10. Second, you find the product of each of the vectors' magnitudes. The magnitude for vector u is ||u|| = sqrt((-3)^2 + (-4)^2) = sqrt(9+16) = sqrt(25) = 5. The magnitude for vector v is ||v|| = sqrt((-2)^2 + (-1)^2) = sqrt(4+1) = sqrt(5). The product of the magnitudes would thus be ||u||||v|| = 5sqrt(5). Third, divide the dot product by the product of the magnitudes which would be u*v/||u||||v|| = 10/5sqrt(5) = 2sqrt(5)/5. Lastly, you take the arccosine of the result which would be theta=cos^-1(2sqrt(5)/5) = 26.56 degrees, which is the angle between vectors u and v.
Answer:
If the confidence level is increased from 90% to 99% for an SRS of size n , the width of the confidence interval for the mean μ will <u>increase</u>.
Step-by-step explanation:
We have been given an incomplete statement. We are supposed to complete the given statement.
If the confidence level is increased from 90% to 99% for an SRS of size n , the width of the confidence interval for the mean μ will:
We know that when confidence level decreases from a value to a lower value, then the confidence interval for the mean decreases.
When confidence level increases from a value to a higher value, then the confidence interval for the mean increases.
When we will increase the confidence level from 90% to 99%, the width of the confidence interval for the mean will also increase, so it will become wider.
Therefore, the correct word for our given statement is increase.