We know that
<span>the regular hexagon can be divided into 6 equilateral triangles
</span>
area of one equilateral triangle=s²*√3/4
for s=3 in
area of one equilateral triangle=9*√3/4 in²
area of a circle=pi*r²
in this problem the radius is equal to the side of a regular hexagon
r=3 in
area of the circle=pi*3²-----> 9*pi in²
we divide that area into 6 equal parts------> 9*pi/6----> 3*pi/2 in²
the area of a segment formed by a side of the hexagon and the circle is equal to <span>1/6 of the area of the circle minus the area of 1 equilateral triangle
</span>so
[ (3/2)*pi in²-(9/4)*√3 in²]
the answer is
[ (3/2)*pi in²-(9/4)*√3 in²]
I don't know the answer, but desmos.com will graph it for you! Hope this helps
Step-by-step explanation:
question number 2 first part X + 2 is equal to 7 .. x is equal to 7 - 2x is equal to 5 ..second part 3 x minus 1 is equal to 3 x is equal to 23 - 1 = 3x=24 x=24÷3=x=8ans
I believe d=4. You can divide pi from both sides (3d=12) and then divide 3 from both sides, which gets you d=4