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Karolina [17]
3 years ago
5

PLEASE HEELP!!!

Physics
1 answer:
Ann [662]3 years ago
8 0

Answer:

The "pressure" of the electricity is electric potential. Electric potential is the amount of energy available to push each unit of charge through an electric circuit. The unit of electric potential is the volt. ... A volt is the force needed to move one amp through a conductor that has 1 ohm of resistance

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How could you demomstrate a complete and incomplete loop in an electrical circut
shutvik [7]

Answer:

A complete circuit is a complete loop with electricity flowing the way it's supposed to flow: from the battery, to the component, and back to the battery again. An open circuit is an incomplete loop, where the loop is broken at a particular point and electricity can't flow at all

Explanation:

So, you can show one with how the electricity flows right through and then how the loop is broken so the electricity wont really flow.

6 0
3 years ago
A race car starting from rest accelerates uniformly at 4.9 m/s^2. What is the car's speed after it has traveled 200 meters?
NeX [460]
The equation v²=u²+2as will help with solving this equation
v is what we are trying to find
u=0
a=4.9
s=200
v²=0²+2*4.9*200
v=√(2*4.9*200)
v=√1960
v=44.3 m/s (3 sf)
5 0
4 years ago
Read 2 more answers
Why doesn't the earth block out the light between the sun and the moon during a normal month
almond37 [142]

Answer:

Explanation:

6 0
3 years ago
A 1.80-m -long uniform bar that weighs 531 N is suspended in a horizontal position by two vertical wires that are attached to th
Readme [11.4K]

Answer:

(a) 498.4 Hz

(b) 442 Hz

Solution:

As per the question:

Length of the wire, L = 1.80 m

Weight of the bar, W = 531 N

The position of the copper wire from the left to the right hand end, x = 0.40 m

Length of each wire, l = 0.600 m

Radius of the circular cross-section, R = 0.250 mm = .250\times 10^{- 3}\ m

Now,

Applying the equilibrium condition at the left end for torque:

T_{Al}.0 + T_{C}(L - x) = W\frac{L}{2}

T_{C}(1.80 - 0.40) = 531\times \frac{1.80}{2}

T_{C} = 341.357\ Nm

The weight of the wire balances the tension in both the wires collectively:

W = T_{Al} + T_{C}

531 = T_{Al} + 341.357

T_{Al} = 189.643\ Nm

Now,

The fundamental frequency is given by:

f = \frac{1}{2L}\sqrt{\frac{T}{\mu}}

where

\mu = A\rho = \pi R^{2}\rho

(a) For the fundamental frequency of Aluminium:

f = \frac{1}{2L}\sqrt{\frac{T_{Al}}{\mu}}

f = \frac{1}{2L}\sqrt{\frac{T_{Al}}{\pi R^{2}\rho_{Al}}}

where

\rho_{l} = 2.70\times 10^{3}\ kg/m^{3}

f = \frac{1}{2\times 0.600}\sqrt{\frac{189.643}{\pi 0.250\times 10^{- 3}^{2}\times 2.70\times 10^{3}}} = 498.4\ Hz

(b)  For the fundamental frequency of Copper:

f = \frac{1}{2L}\sqrt{\frac{T_{C}}{\mu}}

f = \frac{1}{2L}\sqrt{\frac{T_{C}}{\pi R^{2}\rho_{C}}}

where

\rho_{C} = 8.90\times 10^{3}\ kg/m^{3}

f = \frac{1}{2\times 0.600}\sqrt{\frac{341.357}{\pi 0.250\times 10^{- 3}^{2}\times 2.70\times 10^{3}}} = 442\ Hz

7 0
4 years ago
1.A bullet is fired with a velocity of 50m/s at an angle tita to the
VladimirAG [237]

Answer:

b

Explanation:

see how far the bullet goes

7 0
4 years ago
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