Mean = 26.75
Range = 25
The answer is C!
18c
i had this on a tes before
hope this helps
Answer:
53
Step-by-step explanation:
plug in the number in place of the x.
Both the mean and median
Median 80+88= 168/2= 84%
Mean 504/6= 84%
73%,
76%,
80%
88%,
90%,
97%,
Domain: possible x values
Range: possible y values
Solution: domain: all real numbers
Range: y greater than 0