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lora16 [44]
3 years ago
7

Is this a funtion? please help

Mathematics
1 answer:
creativ13 [48]3 years ago
3 0

Answer:

No, it is not

Step-by-step explanation:

Here, we want to check if what we have is a function

For a relation to be a function, the mapping must be one to one or many to one

This mean, for every x there must be one y or for every y, there must can be multiple x

But never is it that there are many y for a single x

Looking at the value 0

on the domain, we can see -2 and 1 as the values

Thus, this is not a function

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6TH grade math please help AP EX
hjlf

Answer:

I think the 1st one would be 10...

Step-by-step explanation:

Because 12-2=10 and 18-8=10.

If I'm wrong, im super sorry

5 0
3 years ago
If 2^n+2-2^n+1+2^n= C*2^n, find the value of C
maxonik [38]

Answer:

c= 1

Step-by-step explanation:

To get rid of (c) on the right side, simply divide 2^n both side. But first collect like terms on the left side so you will get 2^n + 1 which you will then simplify the like term(2^n) and you will left with c= 1.

8 0
3 years ago
The tables show the number of hours students
masha68 [24]
You didn’t include pictures.????
5 0
3 years ago
A community theater sells about 150 tickets to a play each week when it charges $20 per ticket.
Marta_Voda [28]

Answer:

  • r = 12.5p(32 -p)
  • $16 per ticket
  • $3200 maximum revenue

Step-by-step explanation:

The number of tickets sold (q) at some price p is apparently ...

  q = 150 + 25(20 -p)/2 = 150 +250 -12.5p

  q = 12.5(32 -p)

The revenue is the product of the price and the number of tickets sold:

  r = pq

  r = 12.5p(32 -p) . . . . revenue equation

__

The maximum of revenue will be on the line of symmetry of this quadratic function, which is halfway between the zeros at p=0 and p=32. Revenue will be maximized when ...

  p = (0 +32)/2 = 16

The theater should charge $16 per ticket.

__

Maximum revenue will be found by using the above revenue function with p=16.

  r = 12.5(16)(32 -16) = $3200 . . . . maximum revenue

_____

<em>Additional comment</em>

The number of tickets sold at $16 will be ...

  q = 12.5(32 -16) = 200

It might also be noted that if there are variable costs involved, maximum revenue may not correspond to maximum profit.

5 0
2 years ago
Find the equation of the line tangent to y = -3x2 + x - 5 at x = -1
SVEN [57.7K]

\boxed{y+9=7(x+1)}

<h2>Explanation:</h2>

The Point-Slope form of the equation of a line is given by:

y-y_{0}=m(x-x_{0}) \\ \\ \\ Where: \\ \\ m:Slope \\ \\ (x_{0},y_{0}):A \ point

To find the equation of the line tangent to y=-3x^2+x-5 \ at \ x=-1, we need to take the derivative:

\frac{dy}{dx}=-6x+ 1

The slope of the line tangent to y=-3x^2+x-5 at x=-1 can be found evaluationg x=1 in the derivative:

\frac{dy}{dx}\Bigr\rvert_{x=-1}=-6x+ 1 \\ \\ \\ \frac{dy}{dx}\Bigr\rvert_{x=-1}=-6(-1)+ 1 \\ \\ \\  m=\frac{dy}{dx}\Bigr\rvert_{x=-1}=7

Finding the point:

x_{0}=-1 \\ \\ Then: \\ \\ y_{0}=-3(-1)^2-1-5=-9 \\ \\ (x_{0},y_{0})=(-1,-9)

Finally, our line is:

y-(-9)=7(x-(-1)) \\ \\ \boxed{y+9=7(x+1)}

The representation of this problem is shown below.

<h2>Learn more:</h2>

Derivative of functions: brainly.com/question/2142425

#LearnWithBrainly

6 0
3 years ago
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