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Reptile [31]
3 years ago
6

Please help!!!!!!! Thank you!!!!!!!!

Mathematics
2 answers:
mart [117]3 years ago
8 0

Answer:

i th i n k i t s - 4 0 i t h i n k t h i s will help i

Goryan [66]3 years ago
6 0
Try -40, hope this helps!! :)
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Which number variable expression represents the number of inches in y yards?
wlad13 [49]
Answer=36*y

36 inches in 1 yard
36in=1yd

36*y
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The equation of the line through point (- 4, 0) and parallel to the y-axis is
riadik2000 [5.3K]
The gradient of y axis is zero. Since the line is parallel to y axis, its gradient is also zero. This
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3 years ago
Evaluate y(x+x);use x=5,and y=3​
nevsk [136]
3(5+5)

Expand brackets

5+5 is 10

3(10) which is 3*10

answer is 30
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One packet of biscuits requires 2 15/16 and 1 7/8 cups of sugar. Estimated total quantity of both ingredients used in 10 such pa
frez [133]

Answer:

<u>H</u><u>e</u><u>y</u><u> </u><u>M</u><u>a</u><u>t</u><u>e</u><u>!</u><u> </u><u>H</u><u>e</u><u>r</u><u>e</u><u>'</u><u>s</u><u> </u><u>y</u><u>o</u><u>u</u><u>r</u><u> </u><u>a</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u><u>.</u>

Step-by-step explanation:

<em><u>One packet of biscuits requires 2½ cups of flour = \frac{5}{2}25</u></em>

<em><u>One packet of biscuits requires 1 \times \frac{2}{3}1×32</u></em>

<em><u>One packet of biscuits requires 1 \times \frac{2}{3}1×32cups of sugar. = \frac{5}{3}35</u></em>

<em><u>Total ingradiants for one packet of biscuits =</u></em>

<em><u>Total ingradiants for one packet of biscuits =( \frac{5}{2} + \frac{5}{3} ) = \frac{15 + 10}{6} = \frac{25}{6}(25+35)=615+10=625</u></em>

<em><u>Then, total quantity of both ingredients used in 10 such packets of biscuits =</u></em>

<em><u>Then, total quantity of both ingredients used in 10 such packets of biscuits =10 \times ( \frac{25}{6} ) = 5 \times ( \frac{25}{3} ) = \frac{125}{3} = 41 \times \frac{2}{3}10×(625)=5×(325)=3125=41×32</u></em>

Hope it helped you!

7 0
3 years ago
To find the x-intercept, what do you do?
jonny [76]

Answer: To find the x intercept using the equation of the line, plug in 0 for the y variable and solve for x. You can also use the graph of the line to find the x intercept. Just look on the graph for the point where the line crosses the x-axis, which is the horizontal axis. That point is the x intercept.

Step-by-step explanation:

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