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Evgesh-ka [11]
3 years ago
14

Help answering this math question

Mathematics
1 answer:
11111nata11111 [884]3 years ago
7 0

Answer:

The height of the building is: 86.61m

Step-by-step explanation:

Given

The question is illustrated with the attached image

Required

Find h

To solve for h, we apply tangent formula i.e.

\tan(\theta) = \frac{Opposite}{Adjacent}

This gives:

\tan(60) = \frac{h}{50}

Make h the subject

h = 50 * \tan(60)

\tan(60) = \sqrt 3

So, we have:

h = 50 * \sqrt 3

h = 50 * 1.7321

h = 86.61m

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I’m having trouble with this question I need some help please
vivado [14]

Answer:

\frac{1}{2}  \:  \:  \:  \:  \:  \frac{1}{4 \: }  \:  \:  \:  \frac{1}{8}

\frac{4}{8}  \:  \:  \:  \frac{2}{8}  \:  \:  \:  \frac{1}{8}

She ate

\frac{7}{8}

8 0
3 years ago
What is the slope of the line represented by the equation f(t) =2t-6
VARVARA [1.3K]

Answer:

The slope is 2.

Step-by-step explanation:

The given line has equation: f(t)=2t-6.

This is a linear equation in t.

The slope is the coefficient of the independent variable t.

The coefficient of t in  f(t)=2t-6 is 2.

Therefore the slope is 2.

Alternatively,  f(t)=2t-6 is of the form  f(t)=mt+c, where m=2 is the slope.

8 0
4 years ago
Read 2 more answers
Write an equation of the direct variation that includes the point (6,-2)
olga55 [171]

Answer:

y =  -  \frac{1}{3}x

Step-by-step explanation:

The equation of a direct variation is generally written as:

y = mx

Where m is the slope of the equation of the direct variation line.

We want a direct variation equation that contains (6,-2).

We substitute the x=6 and y=-2 to find m.

- 2 =  6m

Divide both sides by 6.

\frac{ - 2}{ 6}  =  \frac{6m}{ 6}

-  \frac{1}{3} = m

The required equation is

y =  -  \frac{1}{3}x

7 0
3 years ago
Does anyone know the answer to this?
devlian [24]

Answer:

No

Step-by-step explanation:

7 0
3 years ago
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Which expression represents the 4th term in the binomial expansion of (e+2f)^10
butalik [34]
The answer depends on what is meant by the "fourth term". By the binomial theorem, one answer could be

\dbinom{10}3e^3(2f)^{10-3}=120e^3(2f)^7=15360e^3f^7

By symmetry, another could be

\dbinom{10}3(2f)^3e^{10-3}=960e^7f^3
7 0
3 years ago
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