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3 years ago

How do we increase power? Do we increase or decrease current (amperage)? Do we increase or decrease voltage

Physics

1 answer:

Cloud [144]3 years ago

6 0

Answer:

Increase the power of a hypothesis test

Use a larger sample. ...

Improve your process. ...

Use a higher significance level (also called alpha or α). ...

Choose a larger value for Differences. ...

Use a directional hypothesis (also called the one-tailed hypothesis).

The two main ways of increasing the current in an electrical circuit are by increasing the voltage or by decreasing the resistance.

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A parallel-plate capacitor has square plates that are 7.20 cm on each side and 3.40 mm apart. The space between the plates is co

Lilit [14]

Answer:

U = 218 nJ

Explanation:

We are given;

Spacing between the plates; d = 3.4 mm = 3.4 × 10^(-3) m

Voltage across the capacitor; V = 96 V

Dimension of the square plates is 7.2cm x 7.2cm.

So, Area = 7.2 × 7.2 = 51.84 cm² = 51.84 × 10^(-4) m²

Permittivity of free space; ε_o = 8.85 × 10^(-12) C²/N.m²

From relative permeability table;

Dielectric constant of Pyrex; k1 = 5.6

Dielectric constant of polystyrene; k2 = 2.56

Now, formula for capacitance of a capacitor with Dielectric is;

C = kC_o

Where, C_o = ε_o(A/d)

Since there are 2 capacitors, d will now be d/2 = (3.4 × 10^(-3))/2 m = 1.7 × 10^(-3)

Since we have 2 capacitor, thus ;

C1 = k1*ε_o*(A/d)

C1 = (5.6 × 8.85 × 10^(-12) × (51.84 × 10^(-4))/(1.7 × 10^(-3))

C1 = 1.51 × 10^(-10) F

Similarly;

C2 = (2.56 × 8.85 × 10^(-12) × (51.84 × 10^(-4))/(1.7 × 10^(-3))

C2 = 0.691 × 10^(-10) F

For capacitors in series, formula for total capacitance(Cs) is;

1/Cs = (1/C1) + (1/C2)

Simplifying this, we have;

Cs = (C1*C2)/(C1 + C2)

Plugging in the relevant values ;

Cs = (1.51 × 10^(-10)*0.691 × 10^(-10))/((1.51 × 10^(-10)) + (0.691 × 10^(-10)))

Cs = 0.474 × 10^(-10) F

The formula for energy stored in a capacitor with 2 Dielectrics is given as;

U = ½Cs*V²

So,

U = ½ × 0.474 × 10^(-10) × 96²

U = 2.18 × 10^(-7) J = 218 × 10^(-9) = 218 nJ

8 0

3 years ago

Why do people make this to the seashore?

Nadya [2.5K]

Answer:

Protecting the Seashore

Seashore Conservation Code

When investigating a seashore it is important to remember that the welfare of the plants and animals must come first. If seaweeds are attached to rocks do not try to pull them off, just examine them where they are growing. Handle animals with great care, returning them to the place where they were found. Anemones and limpets are normally firmly stuck to rocks and any attempt to remove them may result in their death. Replace any large stones that are removed – animals that live on the underside soon die if left exposed.

Pollution Problems

Seas and seashores are under continual threat from pollution. Here are some examples:-

oil rigOil spills, either accidental or deliberate, have a devastating effect on marine life, especially seabirds. Black tar-like oil washed up on a rocky shore would obviously completely destroy the entire community of living things. Chemicals used to disperse oil spills on a shore may effectively clean up the oil, but they can also cleanse the shore of life! The best policy for marine life is to physically remove as much oil as possible and leave the rest to degrade naturally. A rocky shore will recover much more quickly if chemicals are not used.

Sewage and litter also upsets seashore ecosystem, making them unsightly and perhaps contaminated. Some litter can be dangerous to wildlife.

Toxic chemicals and radioactive waste - a cocktail of toxic chemicals have found their way into the sea over the years, affecting both marine and human life. For many years potentially deadly radioactive waste from nuclear power stations and other sources was disposed of in the sea, and beaches have been contaminated by accidental leakages from nuclear power stations.

Explanation:

5 0

3 years ago

Read 2 more answers

A rope is wrapped around a pulley many times. The pulley can be modeled as a solid disk of radius R and mass M, and a mass mA ha

aleksandr82 [10.1K]

The magnitude of the tangential acceleration of the hanging mass is 2mg/MR

<h3>Tangential acceleration of the hanging mass</h3>

The tangential acceleration of the hanging mass around the pulley is determined from the principle of conservation of angular momentum as shown below;

τ = Iα

Where;

I is the moment of inertia
α is the angular velocity

$\alpha = \frac{\tau}{I} \\\\\alpha = \frac{mgR}{3/2MR^2} \\\\\alpha = \frac{2mgR}{3MR^2} \\\\\alpha = \frac{2mg}{3MR}$

Where;

m is the hanging mass
M is the mass of solid disk

The tangential acceleration is calculated as follows;

$a = \alpha R\\\\a = \frac{2mg}{3MR} \times R\\\\a = \frac{2mg}{3M}$

Thus, the magnitude of the tangential acceleration of the hanging mass is 2mg/MR

Learn more about tangential acceleration here: brainly.com/question/11476496

4 0

3 years ago

A 10 Kg dog is running with a speed of 5.0 m/s what is the minimum work required to stop the dog

ra1l [238]

Answer:

25J

Explanation:

Given parameters:

Mass of the dog = 10kg

Speed of the dog = 5m/s

Unknown:

The minimum energy required to stop the dog = ?

Solution:

The dog is moving with a kinetic energy and to stop the dog, an equal amount of kinetic energy generated must be applied to the dog.

To find the kinetic energy;

K.E = $\frac{1}{2}$ m v²

m is the mass

v is the velocity

Now insert the parameters and solve;

K.E = $\frac{1}{2}$ x 10 x 5 = 25J

8 0

3 years ago

How many miles can you get on one tank of gas if your tank holds 18 gallons and you get 22 miles per

MrRissso [65]

Multiply the two. The units will cancel out. 22 miles per gallon can be expressed as 22 miles / 1 gallon, so you can write the following:
18 gallons * 22 miles / 1 gallon
Which simplifies to 18 * 22 miles = 396 miles.

4 0

4 years ago

Read 2 more answers