Answer:
need what?? I would love to help though!
The radius of a sodium atom is determined as 2.145 x 10⁻⁸ cm.
<h3>
What is body-centered cubic unit cell?</h3>
Body-centered cubic (BCC) is the name given to a type of atom arrangement found in nature.
A body-centered cubic unit cell structure consists of atoms arranged in a cube where each corner of the cube shares an atom and with one atom positioned at the center.
<h3>
Volume of the sodium atom</h3>
The volume of the sodium atom is calculated as follows;
V = ZM/Nρ
where;
- Z is 2 for a body-centered cubic unit cell
- M is mass of sodium atom = 23 g/mol
- ρ is density of sodium atom
- N is Avogadro's number
V = (2 x 23) / (6.023 x 10²³ x 0.968)
V = 7.89 x 10⁻²³ cm³
<h3>Edge length of the unit cell</h3>
a = (V)^¹/₃
a = (7.89 x 10⁻²³ cm³)^¹/₃
a = 4.29 x 10⁻⁸ cm
<h3>Radius of the unit cell</h3>
r = a/2
r = ( 4.29 x 10⁻⁸ cm) / 2
r = 2.145 x 10⁻⁸ cm
Thus, the radius of a sodium atom is determined as 2.145 x 10⁻⁸ cm.
Learn more about sodium atom here: brainly.com/question/25033306
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Answer:
Original Mass before 5 days = 82.97 gm
Explanation:
The problem can be solved using simple formula:
How much mass remains = (1 / 2^n) x Original Mass ------ (1)
Since,
How much mass remains = 65.1 gm
n = Number of half-lives during the interval = 5 days / 14.3 days = 0.35
Original Mass = ?
Now, equation (1) implies:
⇒ 65.1 = ( 1 / 2^0.35 ) x Original Mass
⇒ 65.1 = (0.785) x Original Mass
⇒ Original Mass = 82. 97 gm
Alternatively, another formula is:
N(t) = No (1/2)^ (t / t1/2) ------- (2)
where,
Nt = Mass Remains
No = Initial Mass
t = Time
t1/2 = Half Life
Equation (2) implies:
⇒ 65.1 = No (1/2) ^ (5/14.3)
Solving above equation we get,
No = 82.97 gm
Answer:
i would say 10, so the anser is A.
Explanation:
because there are the same number of protons and electrons, therefore for a regular O, you are supposed to have only 8 protons, but it is charged, thus, whatever the charge is will be taken into consideration into how much the proton and electron doe it have. Thus, for this case, it has 10, because the charge is negative and you have 8 electron plus 2 = 10.
Answer:
The correct answer is d. Sn(s) | Sn²⁺(aq) ∥ H⁺(aq) | H₂(g) | Pt
Explanation:
The half reactions are:
2H⁺(aq) + 2 e- ⟶ H₂(g) (reduction)
Sn(s) ⟶ Sn²⁺(aq) + 2 e- (oxidation)
In the cell notation, there are two electrodes in which are separated the reduction reaction from the oxidation reaction. In the left electrode occurs the oxidation reaction (anode) while in the right electrode occurs the reduction reaction (cathode). The general form of the cell notation is the following:
anode reaction∥ cathode reaction
where the two bars ( ∥ ) represent the physical barrier between the electrodes. A single bar ( | ) is used to represent a phase separation.
In this redox reaction, the half reaction of the anode is Sn(s) ⟶ Sn²⁺(aq) + 2 e-; whereas the half reaction of the cathode is 2H⁺(aq) + 2 e- ⟶ H₂(g).
The componens are written in order according to the half reaction. Since Sn²⁺ and H⁺ ions are in solution, a platinum electrode is used and represented as Pt. Thus, the cell notation is:
Sn(s) | Sn²⁺(aq) ∥ H⁺(aq) | H₂(g) | Pt