Answer:
3.14
3.14
3.14
3.14
3.14
I just now realized that these are all 3.14 and that I've done this before, I hope this helps you :)
Step-by-step explanation:
Answer:
7, 9, 11
Step-by-step explanation:
question: Find three consecutive odd integers such that the difference of twice the second and the first is 11.
make the 3 consecutive odd intergers x, y, and z.
numbers are consective (come right after another) AND odd, meaning you would add 2 every time. therefore:
x+2=y
y+2=z
given that: "difference of twice the second and the first is 11."
difference means subtraction
second number is the variable y
first number is the variable x
2y-x=11
----------------
3 equations:
2y-x=11
x+2=y
y+2=z
----------solve by substitution
x+2=y
x =y-2 into 2y-x=11
2y-(y-2)=11
2y-y+2=11
y=9
second number is 9
-----
numbers are 7, 9, 11
X = 2 + (x-2)sqrt
<=> x - 2 = (x - 2)sqrt
<=> x-2 = 0 OR x - 2 = 1
=> x = 2 OR x = 3
The answer is 1/4. You do 6-2/9-(-7). That equals to 4/16, which you simplify to 1/4