Answer:
B. All real numbers
Step-by-step explanation:
I assume the function is f(x) = 3^x, where x is an exponent.
Since an exponent can be a positive number, a negative number, and zero, x can be any real number. The domain of a function is the set of values that can be used for x.
Answer: B. All real numbers
Answer:
3(2x^2-3x+14)
Step-by-step explanation:
6x^2-9x+42
All three terms have a common factor of 3
3(2x^2-3x+14)
Now let's focus on 2x^2-3x+14 and bring down the factor 3 later
so a=2
b=-3
c=14
Let's try to find two factors for ac that multiply to be a*c and add up to be b.
ac=28
b=-3
-----
ac=7(4)=14(2)=8(2)
Even if I made these pairs with both negatives nothing would give me -3
So you can only go as far as 3(2x^2-3x+14)
Here is another thing to help you if you have ax^2+bx+c and b^2-4ac<0 then it can't be factored (over reals)
Yes it is because 5 can not go into 24 without using decimals
<span>5 biscuits=15 pounds.
If you divide 24 by 8 it equals 3 so 1 biscuit=3 pounds, 5x3=15 pounds
</span>